YTU.2575 交通工具信息

Problem A: 交通工具信息

Time Limit: 1 Sec   Memory Limit: 128 MB
Submit: 750   Solved: 421
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Description

有一个交通工具类vehicle，将它为 基类派生的有派生小车类car，卡车类truck和轮船类boat，定义这些类，并使其能够显示其各类交通工具的详细信息。

他们包含的信息，有如下几种：

1.名字    -----与输入的名字相符合

2.时速(km/h)    -----最高时速

3.耗油量(L/100km)    -----在经济时速下测得耗油量

小车类：
250km/h
14.8 L/100km
卡车类：
140km/h
18L/100km
轮船类：
50km/h
8.33L/100km

Input

输入三个派生类对应名字。

Output

输出对应类型的信息。

Sample Input

Mercedes_Benz
Transport_truck
Boat

Sample Output

Mercedes_Benz
250km/h
14.8L/100km
Transport_truck
140km/h
18L/100km
Boat
50km/h
8.33L/100km

AC代码：

#include <iostream>
 
using namespace std;
class Vehicle
{
public:
    Vehicle();
    Vehicle(string sname)
    {
        name=sname;
    }
 void showinfo()
 {
     cout<<name<<endl;
 }
private:
    string name;
};
class Car :public Vehicle
{
public:
    void showinfo()
    {
        cout<<v<<"km/h"<<endl;
        cout<<q<<"L/100km"<<endl;
    }
    Car(string sname):Vehicle(sname),v(250),q(14.8){};
private:
    int v;
    double q;
};
class Truck:public Vehicle
{
    public:
    void showinfo()
    {
        cout<<v<<"km/h"<<endl;
        cout<<q<<"L/100km"<<endl;
    }
    Truck(string sname):Vehicle(sname),v(140),q(18){};
private:
    int v;
    double q;
};
class Boat:public Vehicle
{
    public:
    void showinfo()
    {
        cout<<v<<"km/h"<<endl;
        cout<<q<<"L/100km"<<endl;
    }
    Boat(string sname):Vehicle(sname),v(50),q(8.33){};
private:
    int v;
    double q;
};
int main(){
Vehicle *vp;
 
    string name0,name1,name2;
 
    cin>>name0;
 
    Car car(name0);
 
    cin>>name1;
 
    Truck truck(name1);
 
    cin>>name2;
 
    Boat boat(name2);
 
    vp=&car;
 
    vp->showinfo ();
    Car *vp1;
    vp1=&car;
    vp1->showinfo();
 
    vp=&truck;
 
    vp->showinfo ();
        Truck *vp2;
    vp2=&truck;
    vp2->showinfo();
 
    vp=&boat;
 
    vp->showinfo ();
           Boat *vp3;
    vp3=&boat;
    vp3->showinfo();
 
    return 0;
 
 
 
}