蓝桥杯嵌入式(G4系列)HAL:LCD和LED冲突问题

前言:

        众所周知,蓝桥杯嵌入式提供的STM32G431RBT6单片机存在一个问题,就是LCD和LED冲突。

解决方法:

        在lcd.h文件下,对这三个函数进行修改。

void LCD_WriteReg(u8 LCD_Reg, u16 LCD_RegValue);
void LCD_WriteRAM_Prepare(void);
void LCD_WriteRAM(u16 RGB_Code);

        三个函数在首加上u16 pcout = GPIOC->ODR,尾加上GPIOC->ODR = pcout,在改变GPIOC的ORD寄存器的值前将其保留,直到LCD完成写操作再把值重新赋给GPIOC的ORD寄存器

        效果如下: 

void LCD_WriteReg(u8 LCD_Reg, u16 LCD_RegValue)
{
	u16 pcout = GPIOC->ODR;
	GPIOB->BRR  |= GPIO_PIN_9;  	
	GPIOB->BRR  |= GPIO_PIN_8;  	
	GPIOB->BSRR |= GPIO_PIN_5; 	
	
	GPIOC->ODR = LCD_Reg; 
	GPIOB->BRR  |= GPIO_PIN_5; 
	__nop();
	__nop();
	__nop();	
	GPIOB->BSRR |= GPIO_PIN_5; 
	GPIOB->BSRR |= GPIO_PIN_8; 

	GPIOC->ODR = LCD_RegValue; 
	GPIOB->BRR  |= GPIO_PIN_5; 
	__nop();
	__nop();
	__nop();  
	GPIOB->BSRR |= GPIO_PIN_5; 
	GPIOB->BSRR |= GPIO_PIN_8; 
	GPIOC->ODR = pcout;
}
void LCD_WriteRAM_Prepare(void)
{ 
	u16 pcout = GPIOC->ODR;
	GPIOB->BRR  |=  GPIO_PIN_9;  
	GPIOB->BRR  |=  GPIO_PIN_8; 
	GPIOB->BSRR |=  GPIO_PIN_5; 

	GPIOC->ODR = R34;     
	GPIOB->BRR  |=  GPIO_PIN_5; 
	__nop();
	__nop();
	__nop();    
	GPIOB->BSRR |=  GPIO_PIN_5;
	GPIOB->BSRR |=  GPIO_PIN_8; 
	__nop();
	__nop();
	__nop();  
	GPIOB->BSRR |=  GPIO_PIN_9; 
	GPIOC->ODR = pcout;
}
void LCD_WriteRAM(u16 RGB_Code)
{
	u16 pcout = GPIOC->ODR;
	GPIOB->BRR  |=  GPIO_PIN_9;  
	GPIOB->BSRR |=  GPIO_PIN_8; 
	GPIOB->BSRR |=  GPIO_PIN_5; 

	GPIOC->ODR = RGB_Code;
	GPIOB->BRR  |=  GPIO_PIN_5;
	__nop();
	__nop();
	__nop();  
	GPIOB->BSRR |=  GPIO_PIN_5; 
	GPIOB->BSRR |=  GPIO_PIN_8; 
	__nop();
	__nop();
	__nop();
	GPIOB->BSRR |=  GPIO_PIN_9; 
	GPIOC->ODR = pcout;
}

猜你喜欢

转载自blog.csdn.net/weixin_51651698/article/details/128756375