Meeting HDU - 5521

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将每个集合抽象为一个点 将该集合中的点都挂到上面 不用两两建边

#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define N 0x3f3f3f3f3f3f3f3f

struct node1
{
    int v;
    ll w;
    int next;
};

struct node2
{
    bool friend operator < (node2 n1,node2 n2)
    {
        return n1.val>n2.val;
    }
    ll val;
    int id;
};

priority_queue <node2> que;
node1 edge[2000010];
ll dis1[200010],dis2[200010];
int first[200010],book[200010],ans[100010];
int n,m,num;

void addedge(int u,int v,ll w)
{
    edge[num].v=v;
    edge[num].w=w;
    edge[num].next=first[u];
    first[u]=num++;
    return;
}

void dijkstra(int ss,ll* dis)
{
    node2 cur,tem;
    ll w;
    int i,u,v;
    while(!que.empty()) que.pop();
    for(i=1;i<=n+m;i++) dis[i]=N;
    memset(book,0,sizeof(book));
    tem.id=ss,tem.val=0;
    que.push(tem);
    dis[ss]=0;
    while(!que.empty())
    {
        cur=que.top();
        que.pop();
        u=cur.id;
        if(book[u]) continue;
        //printf("***%d***\n",u);
        book[u]=1;
        for(i=first[u];i!=-1;i=edge[i].next)
        {
            v=edge[i].v,w=edge[i].w;
            if(!book[v]&&dis[v]>dis[u]+w)
            {
                //printf("***%d %lld***\n",v,w);
                dis[v]=dis[u]+w;
                tem.id=v,tem.val=dis[v];
                que.push(tem);
            }
        }
    }
    return;
}

int main()
{
    ll val,minn;
    int t,cas,i,j,gou,id,cnt;
    scanf("%d",&t);
    for(cas=1;cas<=t;cas++)
    {
        scanf("%d%d",&n,&m);
        memset(first,-1,sizeof(first));
        num=0;
        for(i=1;i<=m;i++)
        {
            scanf("%lld%d",&val,&gou);
            for(j=1;j<=gou;j++)
            {
                scanf("%d",&id);
                addedge(id,n+i,val);
                addedge(n+i,id,0);
            }
        }
        dijkstra(1,dis1);
        dijkstra(n,dis2);
        minn=N,cnt=0;
        for(i=1;i<=n;i++)
        {
            if(dis1[i]!=N&&dis2[i]!=N)
            {
                if(minn>max(dis1[i],dis2[i]))
                {
                    minn=max(dis1[i],dis2[i]);
                    cnt=1;
                    ans[cnt]=i;
                }
                else if(minn==max(dis1[i],dis2[i]))
                {
                    cnt++;
                    ans[cnt]=i;
                }
            }
        }
        if(minn==N)
        {
            printf("Case #%d: Evil John\n",cas);
        }
        else
        {
            printf("Case #%d: %lld\n",cas,minn);
            for(i=1;i<=cnt-1;i++)
            {
                printf("%d ",ans[i]);
            }
            printf("%d\n",ans[i]);
        }
    }
    return 0;
}

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转载自blog.csdn.net/sunyutian1998/article/details/80299496
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