python-分发扑克牌

要求:
生成一幅有序扑克牌组,区分花色(不带大小王);洗牌;给四位玩家发牌;
自动帮助四位玩家按花色大小整理好手牌。
解法一

#生成一幅有序扑克牌组,区分花色(不带大小王)
def generate():
    pokers=[]
    poker=[]
    for i in ['红桃','黑桃','方块','桃花']:
        for j in ['A','2','3','4','5','6','7','8','9','10','J','Q','K']:
            poker.append(i)
            poker.append(j)
            pokers.append(poker)
            poker=[]
    return pokers
poker=generate()
#洗牌
import random
random.shuffle(poker)
#给四位玩家发牌
c={}
for k in ['player1','player2','player3','player4']:
    b=random.sample(poker,13)    
    for s in b:
        poker.remove(s)
    c.setdefault(k,b)
#自动帮助四位玩家按花色大小整理好手牌        
import operator
player1=sorted(c['player1'],key=operator.itemgetter(0,1))
print('player1手中的牌:',player1)
player2=sorted(c['player2'],key=operator.itemgetter(0,1))
print('player2手中的牌:',player2)   
player3=sorted(c['player3'],key=operator.itemgetter(0,1))
print('player3手中的牌:',player3)
player4=sorted(c['player4'],key=operator.itemgetter(0,1))
print('player4手中的牌:',player4)

解法二

A=['♥','♠','♦','♣']
B=['A','2','3','4','5','6','7','8','9','10','J','Q','K']
poker=[]
pokers=[]
n=1
for i in A:
    for j in B:
         pokers.append((n,(i+j)))
         n=n+1
print("开始洗牌....")
import random
random.shuffle(pokers)
import time
def xipai(x):
    for i in x:
        pokers.remove(i)
    return pokers
def fapai(y):
    for i in y:
        print(i[1],',',end=" ")
def sortpai(z):
    for i in z:
        print(i[1],',',end=" ")
time.sleep(3)
a=random.sample(pokers,13) 
pokers=xipai(a)   
print("开始给player1发牌:\n")
print(fapai(a))
b=random.sample(pokers,13) 
pokers=xipai(b)   
print("开始给player2发牌:\n")
print(fapai(b))
c=random.sample(pokers,13) 
pokers=xipai(c)   
print("开始给player3发牌:\n")
print(fapai(c))
d=random.sample(pokers,13) 
pokers=xipai(d)   
print("开始给player4发牌:\n")
print(fapai(d))

a.sort()
b.sort()
c.sort()
d.sort()

time.sleep(3)
print("player1的牌:\n")
print(sortpai(a))
print("player2的牌:\n")
print(sortpai(b))
print("player3的牌:\n")
print(sortpai(c))
print("player4的牌:\n")
print(sortpai(d))           

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转载自blog.csdn.net/zztingfeng/article/details/80201454