遍历DOM树,获取子节点

获取子节点的方法有:

 方法  说明
 children()  选取子节点,可以带过滤参数。但只能选择子节点,不能选择孙子节点。
 find()  选取子节点,可以带过滤参数。可以选择子节点及孙子节点。

children()示例:

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<!DOCTYPE html>
< html >
     < head >
         < meta charset = "UTF-8" >
         < title >子节点</ title >
         < script src = "https://ajax.aspnetcdn.com/ajax/jquery/jquery-3.3.1.min.js" ></ script >
         < style >
             .box{
                 border: 1px solid blueviolet;
                 padding: 1px;
                 margin-bottom: 12px;
             }
         </ style >
     </ head >
     < body >
         < div >
             < ul id = "ul" >
                 < li id = "a" >油条</ li >
                 < li id = "b" >包子</ li >
                 < li id = "c" >米饺</ li >
                 < li id = "d" >< a >鱼粉</ a ></ li >
             </ ul >
         </ div >
         < script >
             $('div').children("*").attr("class", "box");
         </ script >
     </ body >
</ html >

find()示例:

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<!DOCTYPE html>
< html >
     < head >
         < meta charset = "UTF-8" >
         < title >子节点</ title >
         < script src = "https://ajax.aspnetcdn.com/ajax/jquery/jquery-3.3.1.min.js" ></ script >
         < style >
             .box{
                 border: 1px solid blueviolet;
                 padding: 1px;
                 margin-bottom: 12px;
             }
         </ style >
     </ head >
     < body >
         < div >
             < ul id = "ul" >
                 < li id = "a" >油条</ li >
                 < li id = "b" >包子</ li >
                 < li id = "c" >米饺</ li >
                 < li id = "d" >< a >鱼粉</ a ></ li >
             </ ul >
         </ div >
         < script >
             $('div').find("ul").attr("class", "box");
         </ script >
     </ body >
</ html >

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转载自www.cnblogs.com/TangGe520/p/9131852.html