模拟人工洗牌。编写一个模拟人工洗牌的程序，讲洗好的牌分别发给四个人。
**输出格式要求："\nNo.%d:" " %c%2d,"
为便于机器评分，假设随机数的种子为1.即srand(1);然后再调用 rand()函数，即可得到与测试用例相同的随机数序列。
基本思路：
1、先将牌的初始化为：
struct card deck[]={
{1,‘C’},{2,‘C’},{3,‘C’},{4,‘C’},{5,‘C’},{6,‘C’},{7,‘C’},
{8,‘C’},{9,‘C’},{10,‘C’},{11,‘C’},{12,‘C’},{13,‘C’},
{1,‘D’},{2,‘D’},{3,‘D’},{4,‘D’},{5,‘D’},{6,‘D’},{7,‘D’},
{8,‘D’},{9,‘D’},{10,‘D’},{11,‘D’},{12,‘D’},{13,‘D’},
{1,‘H’},{2,‘H’},{3,‘H’},{4,‘H’},{5,‘H’},{6,‘H’},{7,‘H’},
{8,‘H’},{9,‘H’},{10,‘H’},{11,‘H’},{12,‘H’},{13,‘H’},
{1,‘S’},{2,‘S’},{3,‘S’},{4,‘S’},{5,‘S’},{6,‘S’},{7,‘S’},
{8,‘S’},{9,‘S’},{10,‘S’},{11,‘S’},{12,‘S’},{13,‘S’},
};
2、随机选择两张牌（调用rand函数。为便于机器评分，假设随机数的种子为1.即srand(1);然后再调用 rand()函数，即可得到与测试用例相同的随机数序列。）交换两张牌。
3、输出交换52次(洗牌）以后的牌。前13张发给第1个人，然后，再13张发给第2个人，。。。
程序运行结果如下：
No.1: C 9, D10, C10, D 5, D 8, D13, H 5, H 1, C 5, D 7, D 1, C11,
No.2: C13, S12, C12, H10, D 2, H 3, S 9, S 6, S 4, S11, C 4, H13,
No.3: S10, H12, D 4, S 1, C 7, S 2, S 8, D 3, H 2, D 9, C 2, H11,
No.4: S13, C 6, S 5, H 9, S 7, C 3, D12, D11, D 6, H 8, C 1, H 7,
#include <stdio.h>
#include <stdlib.h>
struct card
{
int pips;
char suit;
} ;
struct card deck[]={
{
1,'C'},{
2,'C'},{
3,'C'},{
4,'C'},{
5,'C'},{
6,'C'},{
7,'C'},
{
8,'C'},{
9,'C'},{
10,'C'},{
11,'C'},{
12,'C'},{
13,'C'},
{
1,'D'},{
2,'D'},{
3,'D'},{
4,'D'},{
5,'D'},{
6,'D'},{
7,'D'},
{
8,'D'},{
9,'D'},{
10,'D'},{
11,'D'},{
12,'D'},{
13,'D'},
{
1,'H'},{
2,'H'},{
3,'H'},{
4,'H'},{
5,'H'},{
6,'H'},{
7,'H'},
{
8,'H'},{
9,'H'},{
10,'H'},{
11,'H'},{
12,'H'},{
13,'H'},
{
1,'S'},{
2,'S'},{
3,'S'},{
4,'S'},{
5,'S'},{
6,'S'},{
7,'S'},
{
8,'S'},{
9,'S'},{
10,'S'},{
11,'S'},{
12,'S'},{
13,'S'},
};
shuffle(deck)
struct card deck[];
{
int i,j;
srand(1);
for(i=0;i<52;i++)
{
j=rand()%52;
swapcard(&deck[i],&deck[j]);
}
}
swapcard(p,q)
struct card *p,*q;
{
struct card temp;
temp=*p;
*p=*q;
*q=temp;
}
main()
{
int i;
shuffle(deck);
for(i=0;i<52;i++)
if(i%13==0)
printf("\nNo.%d:",i/13+1);
else
printf(" %c%2d,",deck[i].suit,deck[i].pips);
}