Python画PM2.5时间序列图

import pandas as pd
# 作图,先画2019年
data_mean=pd.read_excel('three_year_mean.xlsx')
data_std=pd.read_excel('three_year_std.xlsx')
mean1=data_mean['2019_pm25']
std1=data_std['2019_pm25']
mean2=data_mean['2020_pm25']
std2=data_std['2020_pm25']

%matplotlib inline
import matplotlib.pyplot as plt
import seaborn as sns
import pandas as pd
import matplotlib as mpl
import matplotlib.font_manager as font_manager

# sns.set(font_scale=1.5,style='white')
#修改默认设置
mpl.rcParams["font.family"] = 'Times New Roman'  #默认字体类型
mpl.rcParams["mathtext.fontset"] = 'cm' #数学文字字体
mpl.rcParams["font.size"] = 20   #字体大小
mpl.rcParams["axes.linewidth"] = 1.5   #轴线边框粗细(默认的太粗了)
font = {
    
    'family' : 'Times New Roman',
        'color'  : 'black',
        'weight' : 'normal',
        'size'   : 25,
        }

font1 = font_manager.FontProperties(family='Times New Roman',weight='bold',style='normal', size=20)

fig, ax = plt.subplots(figsize=(12.8,4))

x=data_mean['date']
ymin=mean1-2*std1
ymax=mean1+2*std1
ymean=mean1

ymin1=mean2-2*std2
ymax1=mean2+2*std2
ymean1=mean2

line75=np.ones(len(x))*75

plt.plot(x, ymin, 'b',marker='.',markersize=0.0, linewidth=0.0)
plt.plot(x, ymax, 'b',marker='.',markersize=0.0, linewidth=0.0)
plt.fill_between(x,ymin,ymax,color="#ffdee1",alpha=0.6)
plt.plot(x, ymean, '#fc0402',marker='o',markersize=0, linewidth=3,label='2019')

plt.plot(x, ymin1, 'b',marker='.',markersize=0.0, linewidth=0.0)
plt.plot(x, ymax1, 'b',marker='.',markersize=0.0, linewidth=0.0)
plt.fill_between(x,ymin1,ymax1,color="#a1dfff",alpha=0.6)
plt.plot(x, ymean1, '#56baf1',marker='o',markersize=0, linewidth=3,label='2020')

plt.plot(x, line75, 'k',linestyle='dashed', linewidth=1,label='75 $\mathbf{ ug/m^3}$')

label=['Jan 16', 'Jan 26', 'Feb 5', 'Feb 15','Feb 25', 'Mar 6', 'Mar 16', 'Mar 26']
plt.xticks(pd.date_range('2020-1-16','2020-3-31',freq='10d'),label)
plt.tick_params(which='major',length=6,width=2)

plt.ylim(0,220)

plt.legend(frameon=False,prop=font1)
plt.savefig('Region.jpg',dpi=300)

在这里插入图片描述

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转载自blog.csdn.net/weixin_45577825/article/details/120378968