[LintCode] 15. Permutations

public class Solution {
    /*
     * @param nums: A list of integers.
     * @return: A list of permutations.
     */
    public List<List<Integer>> permute(int[] nums) {
        List<List<Integer>> result = new ArrayList<List<Integer>>();
        Set<Integer> set = new HashSet<>();
        helper(nums,result,set,new ArrayList<>());
        return result;
    }
    void helper(int[] nums,List<List<Integer>> result,Set<Integer> used,List<Integer> each){
        for(int i=0;i<nums.length;i++){
            if(!used.contains(nums[i])){
                each.add(nums[i]);
                used.add(nums[i]);//当前点已经使用
                helper(nums,result,used,each);
                used.remove(nums[i]);
                each.remove(each.size() - 1);
            }
        }
        if(each.size() == nums.length){
            List<Integer> temp = new ArrayList<>();
            temp.addAll(each);
            result.add(temp);
        }
    }
}

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转载自blog.csdn.net/js54100804/article/details/80181965