给你一个正整数 n ,生成一个包含 1 到 n2 所有元素,且元素按顺时针顺序螺旋排列的 n x n 正方形矩阵 matrix 。
示例 1:
输入:n = 3
输出:[[1,2,3],[8,9,4],[7,6,5]]
示例 2:
输入:n = 1
输出:[[1]]
提示:
1 <= n <= 20
#最直观的思路
定义top,left,down,right分别代表四个边界,
随后依次按照四个方向开始遍历即可
class Solution:
def generateMatrix(self, n: int) -> List[List[int]]:
res = [[0] * n for _ in range(n)]
top, left = 0,0
down, right = n-1, n-1
vaule = 1
while(left <= right and top <= down):
for i in range(left, right + 1):
res[top][i] = vaule
vaule += 1
for i in range(top + 1, down + 1):
res[i][right] = vaule
vaule += 1
for i in range(right - 1, left, -1):
res[down][i] = vaule
vaule += 1
for i in range(down, top, -1):
res[i][left] = vaule
vaule += 1
top += 1
down -= 1
left += 1
right -= 1
# print(res)
return res