#define debug qDebug()<<
int main(int argc, char *argv[])
{
std::remove_reference<int&>::type d;
d = 6;
debug d;
}
std::remove_reference<int&>::type去掉了int&中的引用,结果是int,等于:
int d;
d = 6;
应用:
int a = 3;
int &r = a;
std::remove_reference<decltype(r)>::type d;
d = 6;
debug d;