Flask学习
1.先实现数据库增删改查
2.再配合前端实现管理员的账号登录
3.考虑如何在CentOS上部署 安装python3 CentOS部署flask python3
11.23-----------------------再说吧,今天先写会作业,摸了摸了
设置路由参数
@app.route("/user/<user_id>")
def index(user_id)
return “展示的id为%s”%user_id
@app.route("/user/int:user_id")
def index(user_id)
return “展示的id为%s”%user_id
通过给路由器设置参数,使得客户端可以通过url将参数传递到后端
上传文件
今天醉了,整了半天上传文件没办法,最后是因为这个路径问题:
upload_path = os.path.join(basepath, 'static\\uploads',secure_filename(f.filename))
这个\\upload
,windows要注意转义符
还有另外一个:
def create_app():
app = Flask(__name__)
return app
application=create_app()
@application.route('/upload', methods=['POST', 'GET'])
if __name__ == '__main__':
application.run()
这个避免no module named app问题
完整上传文件代码:
app.py:
from flask import Flask, render_template, request,redirect,url_for
from werkzeug.utils import secure_filename
from werkzeug.datastructures import FileStorage
import os
def create_app():
app = Flask(__name__)
return app
application=create_app()
@application.route('/upload', methods=['POST', 'GET'])
def upload():
if request.method == 'POST':
f = request.files['file']
basepath = os.path.dirname(__file__) # 当前文件所在路径
upload_path = os.path.join(basepath, 'static\\uploads',secure_filename(f.filename)) #注意:没有的文件夹一定要先创建,不然会提示没有该路径
f.save(upload_path)
return redirect(url_for('upload'))
return render_template('upload.html')
if __name__ == '__main__':
application.run()
upload.html:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Title</title>
</head>
<body>
<h1>文件上传示例</h1>
<form action="" enctype='multipart/form-data' method='POST'>
<input type="file" name="file">
<input type="submit" value="上传">
</form>
</body>
</html>