luogu part1.1 津津的储蓄计划 (基础题)

p1089

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define INF 0x3f3f3f3f
int main(){
    
    
	int flag=0,ans=0,x,sum=0;;
	for(int i=0;i<12;i++){
    
    
		cin>>x;
		sum+=300;
		sum-=x;
		if(sum<0){
    
    
			cout<<"-"<<i+1;
			flag=1;
			break;
		}
		else if(sum>=100){
    
    
			ans=ans+(sum/100)*100;
			sum-=(sum/100)*100;
		}
	}if(!flag)cout<<ans*1.2+sum;//加sum 

	return 0;
	
}