题目:输入某年某月某日,判断这一天是这一年的第几天? 1.程序分析:以 3 月 5 日为例,应该先把前两个月的加起来,然后再加上 5 天即本年的第几天, 特殊 情况,闰年且输入月份大于 3 时需考虑多加一天
#define _CRT_SECURE_NO_WARNINGS #include <stdlib.h> #include <stdio.h> int main(){ int day, month, year, sum, leap; printf("\nplease input year,month,day\n"); scanf("%d,%d,%d", &year, &month, &day); switch (month)/*先计算某月以前月份的总天数*/ { case 1:sum = 0; break; case 2:sum = 31; break; case 3:sum = 59; break; case 4:sum = 90; break; case 5:sum = 120; break; case 6:sum = 151; break; case 7:sum = 181; break; case 8:sum = 212; break; case 9:sum = 243; break; case 10:sum = 273; break; case 11:sum = 304; break; case 12:sum = 334; break; default:printf("data error"); break; } sum = sum + day; /*再加上某天的天数*/ if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0))/*判断是不是闰年*/ leap = 1; else leap = 0; if (leap == 1 && month>2)/*如果是闰年且月份大于 2,总天数应该加一天*/ sum++; printf("It is the %dth day.", sum); system("pause"); }