Codeforces Round #693(div3.A)

题干

A. Cards for Friends
time limit per test1 second
memory limit per test256 megabytes
inputstandard input
outputstandard output
For the New Year, Polycarp decided to send postcards to all his n friends. He wants to make postcards with his own hands. For this purpose, he has a sheet of paper of size w×h, which can be cut into pieces.

Polycarp can cut any sheet of paper w×h that he has in only two cases:

If w is even, then he can cut the sheet in half and get two sheets of size w2×h;
If h is even, then he can cut the sheet in half and get two sheets of size w×h2;
If w and h are even at the same time, then Polycarp can cut the sheet according to any of the rules above.

After cutting a sheet of paper, the total number of sheets of paper is increased by 1.

Help Polycarp to find out if he can cut his sheet of size w×h at into n or more pieces, using only the rules described above.

Input
The first line contains one integer t (1≤t≤104) — the number of test cases. Then t test cases follow.

Each test case consists of one line containing three integers w, h, n (1≤w,h≤104,1≤n≤109) — the width and height of the sheet Polycarp has and the number of friends he needs to send a postcard to.

Output
For each test case, output on a separate line:

“YES”, if it is possible to cut a sheet of size w×h into at least n pieces;
“NO” otherwise.
You can output “YES” and “NO” in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).

Example
inputCopy
5
2 2 3
3 3 2
5 10 2
11 13 1
1 4 4
outputCopy
YES
NO
YES
YES
YES

#include<bits/stdc++.h>
using namespace std;
int main()
{
    
    
	int t;
	scanf("%d",&t);
	while(t--)
	{
    
    
		int w,h,n;
		scanf("%d%d%d",&w,&h,&n);
		int sum=1;
		while(w%2==0)
		{
    
    
			sum*=2;
			w/=2;
		}
		while(h%2==0)
		{
    
    
			sum*=2;
			h/=2;
		}
		if(sum>=n)
		printf("YES\n");
		else
		printf("NO\n");
	}
} 

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转载自blog.csdn.net/p15008340649/article/details/112381847
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