A. Floor Number
time limit per test1 second
memory limit per test256 megabytes
inputstandard input
outputstandard output
Vasya goes to visit his classmate Petya. Vasya knows that Petya’s apartment number is n.
There is only one entrance in Petya’s house and the distribution of apartments is the following: the first floor contains 2 apartments, every other floor contains x apartments each. Apartments are numbered starting from one, from the first floor. I.e. apartments on the first floor have numbers 1 and 2, apartments on the second floor have numbers from 3 to (x+2), apartments on the third floor have numbers from (x+3) to (2⋅x+2), and so on.
Your task is to find the number of floor on which Petya lives. Assume that the house is always high enough to fit at least n apartments.
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1≤t≤1000) — the number of test cases. Then t test cases follow.
The only line of the test case contains two integers n and x (1≤n,x≤1000) — the number of Petya’s apartment and the number of apartments on each floor of the house except the first one (there are two apartments on the first floor).
Output
For each test case, print the answer: the number of floor on which Petya lives.
Example
inputCopy
4
7 3
1 5
22 5
987 13
outputCopy
3
1
5
77
Note
Consider the first test case of the example: the first floor contains apartments with numbers 1 and 2, the second one contains apartments with numbers 3, 4 and 5, the third one contains apartments with numbers 6, 7 and 8. Therefore, Petya lives on the third floor.
In the second test case of the example, Petya lives in the apartment 1 which is on the first floor.
#include<bits/stdc++.h>
using namespace std;
int main(){
int t;
cin>>t;
while(t--)
{
int n,x;
cin>>n>>x;
int ans = 1+(n-2)/x;
if((n-2)%x)ans++;
if(n <= 2)ans=1;
cout<<ans<<endl;
}
return 0;
}
本题的坑点也就是1.对于一楼的特判2.对于以后的楼层的公寓如果有刚好能整除的则是在下一层。