java — Thread之CountDownLatch的使用

CountDownLatch的简单使用

CountDownLatch的简单介绍:

CountDownLatch类是一个同步计数器,构造时传入int参数,该参数就是计数器的初始值,每调用一次countDown()方法,计数器减1,计数器大于0 时,await()方法会阻塞程序继续执行
CountDownLatch是一个倒计数的锁存器,当计数减至0时触发特定的事件。
CountDownLatch被用来同步一个或多个任务,强制它们等待由其他任务执行的一组操作完成。你可以向CountDownLatch对象设置一个初始计数值,任何在这个对象上调用wait()方法都将阻塞,直至这个计数值达到0。其他任务在结束工作时,可以在该对象上调用凑你countDown()来减小这个计数值。CountDownLatch被设计为只触发一次,计数值不能被重置。如果你需要能够重置计数值的版本,则可以使用CyclicBarrier。

以下是jdk文档上的两个例子,我们可以学习一下。

一、开始信号,阻止任何工人进行,直到司机准备好他们继续进行

package com.linux.huhx.concurreny;

import java.util.concurrent.CountDownLatch;
import java.util.concurrent.TimeUnit;

public class Driver1 {
    
    
    public static void main(String[] args) throws Exception {
    
    
        CountDownLatch startSignal = new CountDownLatch(1);
        CountDownLatch doneSignal = new CountDownLatch(5);
        for (int i = 0; i < 5; ++i) // create and start threads
            new Thread(new TaskWorker(startSignal, doneSignal)).start();
        System.out.println("countDown before.");           // don't let run yet
        startSignal.countDown();      // let all threads proceed
        TimeUnit.SECONDS.sleep(1);
        System.out.println("await before");
        /**
         * 1、由于doneSignal里面的初始count=5,所以主线程在此会阻塞。
         * 2、当所有的子线程执行完(doneSignal.countDown())之后,此时的count=0。所以后面代码可以继续执行。
         */
        doneSignal.await();
        System.out.println("await after");
    }

    private static class TaskWorker implements Runnable {
    
    
        private final CountDownLatch startSignal;
        private final CountDownLatch doneSignal;

        public TaskWorker(CountDownLatch startSignal, CountDownLatch doneSignal) {
    
    
            this.startSignal = startSignal;
            this.doneSignal = doneSignal;
        }
//需要获取资料的朋友请加Q君样:290194256*

        @Override
        public void run() {
    
    
            try {
    
    
                /**
                 * 1、刚进来的时候,由于startSignal的count=1。所以await()方法阻塞于此。
                 * 2、当主线程执行了startSignal.countDown();此时的startSignal的count=0。所以子线程可以正常运行。
                 */
                startSignal.await();
                doSomeWork();
                doneSignal.countDown();
            } catch (InterruptedException e) {
    
    
                e.printStackTrace();
            }
        }

        private void doSomeWork() {
    
    
            System.out.println("in run method: " + Thread.currentThread().getName());
        }
    }
}

执行的结果如下:子线程的执行顺序不固定

countDown before.
in run method: Thread-0
in run method: Thread-1
in run method: Thread-2
in run method: Thread-4
in run method: Thread-3
await before
await after

调用countDown()的任务在产生这个调用时并没有阻塞,只有对await()的调用会被阻塞,直至计数值到达0。

二、完成信号,允许司机等到所有工人完成为止

package com.linux.huhx.concurreny;

import java.util.Random;
import java.util.concurrent.CountDownLatch;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;

public class Driver2 {
    
    
    public static void main(String[] args) throws Exception {
    
    
        CountDownLatch doneSignal = new CountDownLatch(5);
        ExecutorService service = Executors.newFixedThreadPool(3);
        for (int i = 0; i < 5; ++i) // create and start threads
            service.execute(new WorkerRunnable(doneSignal, i));
        System.out.println("await before");
        doneSignal.await();
        System.out.println("await after");
        service.shutdown();
    }

    private static class WorkerRunnable implements Runnable {
    
    
        private final CountDownLatch doneSignal;
        private final int i;

        public WorkerRunnable(CountDownLatch doneSignal, int i) {
    
    
            this.doneSignal = doneSignal;
            this.i = i;
        }
//需要获取资料的朋友请加Q君样:290194256*

        @Override
        public void run() {
    
    
            doWork(i);
            try {
    
    
                Thread.sleep(new Random().nextInt(1000));
                doneSignal.countDown();
            } catch (InterruptedException e) {
    
    
                e.printStackTrace();
            }
        }

        private void doWork(int i) {
    
    
            System.out.println("in run method: " + i + " " + Thread.currentThread().getName());
        }
    }
}

运行的结果如下:子线程的执行顺序不固定

await before
in run method: 0 pool-1-thread-1
in run method: 2 pool-1-thread-3
in run method: 1 pool-1-thread-2
in run method: 3 pool-1-thread-1
in run method: 4 pool-1-thread-2
await after

在这里插入图片描述
在这里插入图片描述
最新2020整理收集的一些高频面试题(都整理成文档),有很多干货,包含mysql,netty,spring,线程,spring cloud、jvm、源码、算法等详细讲解,也有详细的学习规划图,面试题整理等,需要获取这些内容的朋友请加Q君样:290194256*

猜你喜欢

转载自blog.csdn.net/weixin_53341657/article/details/112912334