create table dlmis.toStudent(
StudentName varchar2(20),
Score integer,
序号 integer,
排名 integer
)
insert into dlmis.toStudent values('AA',1,null,null);
insert into dlmis.toStudent values('BB',2,null,null);
insert into dlmis.toStudent values('CC',3,null,null);
insert into dlmis.toStudent values('DD',4,null,null);
insert into dlmis.toStudent values('EE',5,null,null);
insert into dlmis.toStudent values('FF',6,null,null);
insert into dlmis.toStudent values('HH',4,null,null);
insert into dlmis.toStudent values('GG',null,null,null);
select * from dlmis.toStudent;
update dlmis.toStudent set score = 0 where Score is null;
update dlmis.toStudent t
set (t.序号,t.排名) =
(
select rn,rn2 from (
select StudentName, row_number() over (order by score desc) as rn,
dense_rank() over (order by score desc) as rn2
from dlmis.toStudent
)where StudentName = t.StudentName
)
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分享:分析函数中dense_rank()在出现相同排名时序号是相同的,
row_number返回的是一个连续递增的序号 。