文章目录
T1【GDKOI 2021普及组DAY1】地图 (map)
比较显然的数学规律题,直接上代码
#include<bits/stdc++.h>
#define Fu(i,a,b) for(int i=(a);i<=(b);i++)
#define Fd(i,a,b) for(int i=(a);i>=(b);i--)
#define fre(x) freopen(#x".in","r",stdin),freopen(#x".out","w",stdout)
using namespace std;
int n,a[2005][2005],b1,b2,num1,num2,js1,js2;
bool bj1[2005],bj2[2005];
int main(){
fre(map);
scanf("%d",&n);
Fu(i,1,n) Fu(j,1,n) scanf("%d",&a[i][j]);
if(a[1][1]){
printf("1 1");
return 0;
}
Fu(i,1,n) b1^=a[i][n],b2^=a[n][i];
Fu(i,2,n-1){
int c1=0,c2=0;
Fu(j,2,n){
c1^=a[j][i];
c2^=a[i][j];
}
bj1[i]=a[1][i]^(b1^c1);
bj2[i]=a[i][1]^(b2^c2);
}
Fu(i,2,n-1){
if(bj1[i]) num1++,js1=i;
if(bj2[i]) num2++,js2=i;
}
if(num1==0&&num2==1) printf("%d 1",js2);
else if(num1==1&&num2==0) printf("1 %d",js1);
else if(num1>1&&num2==0) printf("1 %d",n);
else if(num1==0&&num2>0) printf("%d 1",n);
else if(num1==1&&num2==1) printf("%d %d",js2,js1);
else if(num1>1&&num2==1) printf("%d %d",js2,n);
else if(num1==1&&num2>1) printf("%d %d",n,js1);
else printf("%d %d",n,n);
return 0;
}
T2【GDKOI 2021普及组DAY1】灌水 (water)
第一眼,暴力;
第二眼,要不优化一下;
第三眼,倍增;
第四眼,直接AC
首先,设 l [ i , j ] l[i,j] l[i,j]表示这个位置,左边第 2 j 2^j 2j高的地方, r [ i , j ] r[i,j] r[i,j]表示这个位置,右边第 2 j 2^j 2j高的地方
倍增乱搞
#include<bits/stdc++.h>
#define Fu(i,a,b) for(int i=(a);i<=(b);i++)
#define Fd(i,a,b) for(int i=(a);i>=(b);i--)
#define fre(x) freopen(#x".in","r",stdin),freopen(#x".out","w",stdout)
inline int read(){
int f=1,x=0; char s=getchar(); while(s<'0'||s>'9') {
if (s=='-') f=-1; s=getchar(); } while(s>='0'&&s<='9') {
x=x*10+s-'0'; s=getchar(); } return x*f; }
using namespace std;
int l[200005][20],r[200005][20],n,q;
long long a[200005],sum[200005];
int find_l(int o,long long num){
if(a[o-1]>num) return o-1;
int w=o-1;
Fd(j,19,0){
if(a[l[w][j]]<num){
w=l[w][j];
}
}
return l[w][0];
}
int find_r(int o,long long num){
if(a[o+1]>num) return o+1;
int w=o+1;
Fd(j,19,0){
if(a[r[w][j]]<num){
w=r[w][j];
}
}
return r[w][0];
}
int main(){
fre(water);
scanf("%d%d",&n,&q);
Fu(i,1,n){
scanf("%lld",&a[i]);
sum[i]=sum[i-1]+a[i];
Fu(j,0,19) r[i][j]=n+1;
}
a[0]=a[n+1]=10000000005;
Fu(i,1,n){
l[i][0]=find_l(i,a[i]);
Fu(j,1,19) l[i][j]=l[l[i][j-1]][j-1];
}
Fd(i,n,1){
r[i][0]=find_r(i,a[i]);
Fu(j,1,19) r[i][j]=r[r[i][j-1]][j-1];
}
Fu(i,1,q){
int x;
long long y;
scanf("%d%lld",&x,&y);
int ll=find_l(x,y-1),rr=find_r(x,y-1);
long long u=y*(rr-ll-1)-sum[rr-1]+sum[ll];
printf("%lld\n",u);
}
return 0;
}
T3【GDKOI 2021普及组DAY1】配对(match)
#include<bits/stdc++.h>
#define Fu(i,a,b) for(int i=(a);i<=(b);i++)
#define Fd(i,a,b) for(int i=(a);i>=(b);i--)
#define fre(x) freopen(#x".in","r",stdin),freopen(#x".out","w",stdout)
using namespace std;
int n,ll,rr,a[1000005],ans;
int main(){
fre(match);
scanf("%d%d%d",&n,&ll,&rr);
Fu(i,1,n) scanf("%d",&a[i]);
sort(a+1,a+1+n);
int l=1,r=n;
while(l<r){
if(a[l]+a[r]>rr) r--,ans++;
else if(a[l]+a[r]<ll) l++,ans++;
else l++,r--;
if(l==r) ans++;
}
printf("%d",ans);
return 0;
}
T4【GDKOI 2021普及组DAY1】旅行(travel)
#include<bits/stdc++.h>
#define Fu(i,a,b) for(int i=(a);i<=(b);i++)
#define Fd(i,a,b) for(int i=(a);i>=(b);i--)
#define fre(x) freopen(#x".in","r",stdin),freopen(#x".out","w",stdout)
using namespace std;
inline int read(){
int f=1,x=0; char s=getchar(); while(s<'0'||s>'9') {
if (s=='-') f=-1; s=getchar(); } while(s>='0'&&s<='9') {
x=x*10+s-'0'; s=getchar(); } return x*f; }
int n,m,q,ans[200005],fa[200005],size[200005],js=1;
int find(int x){
return fa[x]=fa[x]==x?x:find(fa[x]);
}
struct node{
int x,z,num;
}b[200005];
struct egde{
int u,v,w;
}a[400005];
bool cmp1(egde x,egde y){
return x.w<y.w; }
bool cmp2(node x,node y){
return x.z<y.z; }
int main(){
fre(travel);
n=read(),m=read();
Fu(i,1,m) a[i].u=read(),a[i].v=read(),a[i].w=read();
Fu(i,1,n) fa[i]=i,size[i]=1;
sort(a+1,a+1+m,cmp1);
q=read();
Fu(i,1,q){
b[i].x=read(),b[i].z=read();
b[i].num=i;
}
sort(b+1,b+1+q,cmp2);
a[m+1].w=0x7fffffff;
Fu(i,1,m+1){
while(b[js].z<a[i].w&&js<=q){
ans[b[js].num]=size[find(b[js].x)];
js++;
}
if(find(a[i].v)!=find(a[i].u)){
size[find(a[i].v)]+=size[find(a[i].u)];
fa[find(a[i].u)]=find(a[i].v);
}
}
Fu(i,1,q) printf("%d\n",ans[i]);
return 0;
}
分数100+100+100+35=335
改题100+100+100+100=400
总结
发挥一般,本来能AK。