多目标 benchmark 函数

MOP系列

MOP1:

                                                        { f 1 ( x ) = ( 1 + g ( x ) ) x 1 f 2 ( x ) = ( 1 + g ( x ) ) ( 1 − x 1 ) \left\{\begin{array}{l}f_{1}(x)=(1+g(x)) x_{1} \\ f_{2}(x)=(1+g(x))(1-\sqrt{x_{1}})\end{array}\right. { f1(x)=(1+g(x))x1f2(x)=(1+g(x))(1x1 )

where
        g ( x ) = 2 sin ⁡ ( π x 1 ) ∑ i = 2 n ( − 0.9 t i 2 + ∣ t i ∣ 0.6 ) g(x)=2 \sin \left(\pi x_{1}\right) \sum_{i=2}^{n}\left(-0.9 t_{i}^{2}+\left|t_{i}\right|^{0.6}\right) g(x)=2sin(πx1)i=2n(0.9ti2+ti0.6);
        t i = x i − sin ⁡ ( 0.5 π x 1 ) t_{i}=x_{i}-\sin \left(0.5 \pi x_{1}\right) ti=xisin(0.5πx1);

its PF is        f 2 = 1 − f 1 , 0 ≤ f 1 ≤ 1 f_{2}=1-\sqrt{f_{1}}, 0 \leq f_{1} \leq 1 f2=1f1 ,0f11;
its PS is        { ( x 1 , ⋯   , x n ) ∣ 0 < x 1 < 1 , x j = sin ⁡ ( 0.5 π x 1 ) \left\{\left(x_{1}, \cdots, x_{n}\right) \mid 0<x_{1}<1, x_{j}=\sin \left(0.5 \pi x_{1}\right)\right. { (x1,,xn)0<x1<1,xj=sin(0.5πx1); j = 2 , … , n ;  or  x 1 = 0 , 1. } \left.j=2, \ldots, n ; \text { or } x_{1}=0,1 .\right\} j=2,,n; or x1=0,1.}.

        Domain: [ 0 , 1 ] n [0,1]^{n} [0,1]n; Number of Variables = 10
       

MOP2:

                                               { f 1 ( x ) = ( 1 + g ( x ) ) x 1 f 2 ( x ) = ( 1 + g ( x ) ) ( 1 − x 1 2 ) \left\{\begin{array}{l}f_{1}(x)=(1+g(x)) x_{1} \\ f_{2}(x)=(1+g(x))\left(1-x_{1}^{2}\right)\end{array}\right. { f1(x)=(1+g(x))x1f2(x)=(1+g(x))(1x12)

where

        g ( x ) = 10 sin ⁡ ( π x 1 ) ∑ i = 2 n ∣ t i ∣ 1 + e 5 ∣ t i ∣ g(x)=10 \sin \left(\pi x_{1}\right) \sum_{i=2}^{n} \frac{\left|t_{i}\right|}{1+e^{5\left|t_{i}\right|}} g(x)=10sin(πx1)i=2n1+e5titi;
        t i = x i − sin ⁡ ( 0.5 π x 1 ) t_{i}=x_{i}-\sin \left(0.5 \pi x_{1}\right) ti=xisin(0.5πx1);

its PF is        f 2 = 1 − f 1 2 , 0 ≤ f 1 ≤ 1 f_{2}=1-f_{1}^{2}, 0 \leq f_{1} \leq 1 f2=1f12,0f11;
its PS is         { ( x 1 , ⋯   , x n ) ∣ 0 < x 1 < 1 , x j = sin ⁡ ( 0.5 π x 1 ) \left\{ \left( { {x}_{1}},\cdots ,{ {x}_{n}} \right)\mid 0<{ {x}_{1}}<1,{ {x}_{j}}=\sin \left( 0.5\pi { {x}_{1}} \right) \right. { (x1,,xn)0<x1<1,xj=sin(0.5πx1); j = 2 , … , n ;  or  x 1 = 0 , 1. } \left.j=2, \ldots, n ; \text { or } x_{1}=0,1 .\right\} j=2,,n; or x1=0,1.}.

        Domain: [ 0 , 1 ] n [0,1]^{n} [0,1]n; Number of Variables = 10
       

MOP3:

在这里插入图片描述

where
                        g ( x ) = 10 sin ⁡ ( π x 1 2 ) ∑ i = 2 n ∣ t i ∣ 1 + e 5 ∣ t i ∣ g(x)=10 \sin \left(\frac{\pi x_{1}}{2}\right) \sum_{i=2}^{n} \frac{\left|t_{i}\right|}{1+e^{5\left|t_{i}\right|}} g(x)=10sin(2πx1)i=2n1+e5titi;
                        t i = x i − sin ⁡ ( 0.5 π x 1 ) t_{i}=x_{i}-\sin \left(0.5 \pi x_{1}\right) ti=xisin(0.5πx1);
its PF is         f 2 = 1 − f 1 2 , 0 ≤ f 1 ≤ 1 f_{2}=\sqrt{1-f_{1}^{2}}, 0 \leq f_{1} \leq 1 f2=1f12 ,0f11;
its PS is         { ( x 1 , ⋯   , x n ) ∣ 0 < x 1 ≤ 1 , x j = sin ⁡ ( 0.5 π x 1 ) \left\{\left(x_{1}, \cdots, x_{n}\right) \mid 0<x_{1} \leq 1, x_{j}=\sin \left(0.5 \pi x_{1}\right)\right. { (x1,,xn)0<x11,xj=sin(0.5πx1); j = 2 , … , n ;  or  x 1 = 0 , 1. } \left.j=2, \ldots, n ; \text { or } x_{1}=0,1 .\right\} j=2,,n; or x1=0,1.}.

        Domain: [ 0 , 1 ] n [0,1]^{n} [0,1]n; Number of Variables = 10
       

MOP4:

在这里插入图片描述

where
                        g ( x ) = 10 sin ⁡ ( π x 1 ) ∑ i = 2 n ∣ t i ∣ 1 + e 5 ∣ t i ∣ g(x)=10 \sin \left(\pi x_{1}\right) \sum_{i=2}^{n} \frac{\left|t_{i}\right|}{1+e^{5 \mid t_{i}} \mid} g(x)=10sin(πx1)i=2n1+e5titi;
                        t i = x i − sin ⁡ ( 0.5 π x 1 ) t_{i}=x_{i}-\sin \left(0.5 \pi x_{1}\right) ti=xisin(0.5πx1);

its PF is         discontinuous;
its PS is         { ( x 1 , ⋯   , x n ) ∣ 0 < x 1 < 1 , x j = sin ⁡ ( 0.5 π x 1 ) \left\{\left(x_{1}, \cdots, x_{n}\right) \mid 0<x_{1}<1, x_{j}=\sin \left(0.5 \pi x_{1}\right)\right. { (x1,,xn)0<x1<1,xj=sin(0.5πx1); j = 2 , … , n ;  or  x 1 = 0 , 1. } \left.j=2, \ldots, n ; \text { or } x_{1}=0,1 .\right\} j=2,,n; or x1=0,1.}.

        Domain: [ 0 , 1 ] n [0,1]^{n} [0,1]n; Number of Variables = 10
       

MOP5:

                                                        { f 1 ( x ) = ( 1 + g ( x ) ) x 1 f 2 ( x ) = ( 1 + g ( x ) ) ( 1 − x 1 ) \left\{\begin{array}{l}f_{1}(x)=(1+g(x)) x_{1} \\ f_{2}(x)=(1+g(x))(1-\sqrt{x_{1}})\end{array}\right. { f1(x)=(1+g(x))x1f2(x)=(1+g(x))(1x1 )

where

                        g ( x ) = 2 ∣ cos ⁡ ( π x 1 ) ∣ ∑ i = 2 n ( − 0.9 t i 2 + ∣ t i ∣ 0.6 ) g(x)=2\left|\cos \left(\pi x_{1}\right)\right| \sum_{i=2}^{n}\left(-0.9 t_{i}^{2}+\left|t_{i}\right|^{0.6}\right) g(x)=2cos(πx1)i=2n(0.9ti2+ti0.6);
                        t i = x i − sin ⁡ ( 0.5 π x 1 ) t_{i}=x_{i}-\sin \left(0.5 \pi x_{1}\right) ti=xisin(0.5πx1);

its PF is         f 2 = 1 − f 1 , 0 ≤ f 1 ≤ 1 f_{2}=1-\sqrt{f_{1}}, 0 \leq f_{1} \leq 1 f2=1f1 ,0f11;
its PS is         { ( x 1 , ⋯   , x n ) ∣ 0 ≤ x 1 ≤ 1 , x j = sin ⁡ ( 0.5 π x 1 ) \left\{\left(x_{1}, \cdots, x_{n}\right) \mid 0 \leq x_{1} \leq 1, x_{j}=\sin \left(0.5 \pi x_{1}\right)\right. { (x1,,xn)0x11,xj=sin(0.5πx1); j = 2 , … , n ;  or  x 1 = 0.5 } \left.j=2, \ldots, n ; \text { or } x_{1}=0.5\right\} j=2,,n; or x1=0.5}.

        Domain: [ 0 , 1 ] n [0,1]^{n} [0,1]n; Number of Variables = 10

MOP6:

                                        { f 1 ( x ) = ( 1 + g ( x ) ) x 1 x 2 f 2 ( x ) = ( 1 + g ( x ) ) x 1 ( 1 − x 2 ) f 3 ( x ) = ( 1 + g ( x ) ) ( 1 − x 1 ) \left\{\begin{array}{l}f_{1}(x)=(1+g(x)) x_{1} x_{2} \\ f_{2}(x)=(1+g(x)) x_{1}\left(1-x_{2}\right) \\ f_{3}(x)=(1+g(x))\left(1-x_{1}\right)\end{array}\right. f1(x)=(1+g(x))x1x2f2(x)=(1+g(x))x1(1x2)f3(x)=(1+g(x))(1x1)

where

                        g ( x ) = 2 sin ⁡ ( π x 1 ) ∑ i = 3 n ( − 0.9 t i 2 + ∣ t i ∣ 0.6 ) g(x)=2\sin \left( \pi { {x}_{1}} \right)\sum\limits_{i=3}^{n}{\left( -0.9t_{i}^{2}+{ {\left| { {t}_{i}} \right|}^{0.6}} \right)} g(x)=2sin(πx1)i=3n(0.9ti2+ti0.6);
                        t i = x i − x 1 x 2 { {t}_{i}}={ {x}_{i}}-{ {x}_{1}}{ {x}_{2}} ti=xix1x2;

its PF is         f 1 + f 2 + f 3 = 1 , 0 ≤ f 1 , f 2 , f 3 ≤ 1 { {f}_{1}}+{ {f}_{2}}+{ {f}_{3}}=1,0\le { {f}_{1}},{ {f}_{2}},{ {f}_{3}}\le 1 f1+f2+f3=1,0f1,f2,f31;
its PS is         { ( x 1 , ⋯   , x n ) ∣ 0 < x 1 < 1 , 0 ≤ x 2 ≤ 1 \left\{ \left( { {x}_{1}},\cdots ,{ {x}_{n}} \right)\mid 0<{ {x}_{1}}<1,0\le { {x}_{2}}\le 1 \right. { (x1,,xn)0<x1<1,0x21; x j = x 1 x 2 , j = 3 , … , n ;  or  x 1 = 0 , 1. } \left. { {x}_{j}}={ {x}_{1}}{ {x}_{2}},j=3,\ldots ,n;\text{ or }{ {x}_{1}}=0,1. \right\} xj=x1x2,j=3,,n; or x1=0,1.}

        Domain: [ 0 , 1 ] n [0,1]^{n} [0,1]n; Number of Variables = 10
       

MOP7:

在这里插入图片描述

where

                      g ( x ) = 2 sin ⁡ ( π x 1 ) ∑ i = 3 n ( − 0.9 t i 2 + ∣ t i ∣ 0.6 ) g(x)=2\sin \left( \pi { {x}_{1}} \right)\sum\limits_{i=3}^{n}{\left( -0.9t_{i}^{2}+{ {\left| { {t}_{i}} \right|}^{0.6}} \right)} g(x)=2sin(πx1)i=3n(0.9ti2+ti0.6);
                      t i = x i − x 1 x 2 { {t}_{i}}={ {x}_{i}}-{ {x}_{1}}{ {x}_{2}} ti=xix1x2;

its PF is         f 1 2 + f 2 2 + f 3 2 = 1 , 0 ≤ f 1 , f 2 , f 3 ≤ 1 f_{1}^{2}+f_{2}^{2}+f_{3}^{2}=1,0\le { {f}_{1}},{ {f}_{2}},{ {f}_{3}}\le 1 f12+f22+f32=1,0f1,f2,f31;
its PS is         { ( x 1 , ⋯   , x n ) ∣ 0 < x 1 < 1 , 0 ≤ x 2 ≤ 1 \left\{ \left( { {x}_{1}},\cdots ,{ {x}_{n}} \right)\mid 0<{ {x}_{1}}<1,0\le { {x}_{2}}\le 1 \right. { (x1,,xn)0<x1<1,0x21; x j = x 1 x 2 , j = 3 , … , n ;  or  x 1 = 0 , 1. } \left. { {x}_{j}}={ {x}_{1}}{ {x}_{2}},j=3,\ldots ,n;\text{ or }{ {x}_{1}}=0,1. \right\} xj=x1x2,j=3,,n; or x1=0,1.}.

        Domain: [ 0 , 1 ] n [0,1]^{n} [0,1]n; Number of Variables = 10
       
       

F系列

       

F1:

                      f 1 ( x ) = ( 1 + g ( x ) ) x 1 f_{1}(x)=(1+g(x)) x_{1} f1(x)=(1+g(x))x1
                      f 2 ( x ) = ( 1 + g ( x ) ) ( 1 − x 1 ) 5 f_{2}(x)=(1+g(x))(1-\sqrt{x_{1}})^{5} f2(x)=(1+g(x))(1x1 )5
                      g ( x ) = 2 sin ⁡ ( 0.5 π x 1 ) ( n − 1 + ∑ i = 2 n ( y i 2 − cos ⁡ ( 2 π y i ) ) ) g(x)=2 \sin \left(0.5 \pi x_{1}\right)\left(n-1+\sum_{i=2}^{n}\left(y_{i}^{2}-\cos \left(2 \pi y_{i}\right)\right)\right) g(x)=2sin(0.5πx1)(n1+i=2n(yi2cos(2πyi)))

where

                      y i = 2 : n = x i − sin ⁡ ( 0.5 π x i ) y_{i=2: n}=x_{i}-\sin \left(0.5 \pi x_{i}\right) yi=2:n=xisin(0.5πxi)
       

POF:         f 2 = ( 1 − f 1 ) 5 f_{2}=(1-\sqrt{f_{1}})^{5} f2=(1f1 )5
POS:         x i = sin ⁡ ( 0.5 π x i ) , i = 2 , … , n x_{i}=\sin \left(0.5 \pi x_{i}\right), i=2, \ldots, n xi=sin(0.5πxi),i=2,,n

       Domain: [ 0 , 1 ] n [0,1]^{n} [0,1]n; Number of Variables = 30
       

F2:

                      f 1 ( x ) = ( 1 + g ( x ) ) ( 1 − x 1 ) f_{1}(x)=(1+g(x))\left(1-x_{1}\right) f1(x)=(1+g(x))(1x1)
                      f 2 ( x ) = 1 2 ( 1 + g ( x ) ) ( x 1 + x 1 cos ⁡ 2 ( 4 π x 1 ) ) f_{2}(x)=\frac{1}{2}(1+g(x))\left(x_{1}+\sqrt{x_{1}} \cos ^{2}\left(4 \pi x_{1}\right)\right) f2(x)=21(1+g(x))(x1+x1 cos2(4πx1))
                      g ( x ) = 2 sin ⁡ ( 0.5 π x 1 ) ( n − 1 + ∑ i = 2 n ( y i 2 − cos ⁡ ( 2 π y i ) ) ) g(x)=2 \sin \left(0.5 \pi x_{1}\right)\left(n-1+\sum_{i=2}^{n}\left(y_{i}^{2}-\cos \left(2 \pi y_{i}\right)\right)\right) g(x)=2sin(0.5πx1)(n1+i=2n(yi2cos(2πyi)))

where

                      y i = 2 : n = x i − sin ⁡ ( 0.5 π x i ) y_{i=2: n}=x_{i}-\sin \left(0.5 \pi x_{i}\right) yi=2:n=xisin(0.5πxi)
       

POF:         f 2 = 1 2 ( 1 − f 1 + 1 − f 1 cos ⁡ 2 ( 4 π ( 1 − f 1 ) ) ) f_{2}=\frac{1}{2}\left(1-f_{1}+\sqrt{1-f_{1}} \cos ^{2}\left(4 \pi\left(1-f_{1}\right)\right)\right) f2=21(1f1+1f1 cos2(4π(1f1)))
POS:         x i = sin ⁡ ( 0.5 π x i ) , i = 2 , … , n x_{i}=\sin \left(0.5 \pi x_{i}\right), i=2, \ldots, n xi=sin(0.5πxi),i=2,,n

       Domain: [ 0 , 1 ] n [0,1]^{n} [0,1]n; Number of Variables = 30
       

F3:

                      f 1 ( x ) = ( 1 + g ( x ) ) x 1 f_{1}(x)=(1+g(x)) x_{1} f1(x)=(1+g(x))x1
                      f 2 ( x ) = 1 2 ( 1 + g ( x ) ) ( 1 − x 1 0.1 + ( 1 − x 1 ) 2 cos ⁡ 2 ( 3 π x 1 ) ) f_{2}(x)=\frac{1}{2}(1+g(x))\left(1-x_{1}^{0.1}+(1-\sqrt{x_{1}})^{2} \cos ^{2}\left(3 \pi x_{1}\right)\right) f2(x)=21(1+g(x))(1x10.1+(1x1 )2cos2(3πx1))
                      g ( x ) = 2 sin ⁡ ( 0.5 π x 1 ) ( n − 1 + ∑ i = 2 n ( y i 2 − cos ⁡ ( 2 π y i ) ) ) g(x)=2 \sin \left(0.5 \pi x_{1}\right)\left(n-1+\sum_{i=2}^{n}\left(y_{i}^{2}-\cos \left(2 \pi y_{i}\right)\right)\right) g(x)=2sin(0.5πx1)(n1+i=2n(yi2cos(2πyi)))

where
                      y i = 2 : n = x i − sin ⁡ ( 0.5 π x i ) y_{i=2: n}=x_{i}-\sin \left(0.5 \pi x_{i}\right) yi=2:n=xisin(0.5πxi)
       

POF:         f 2 = 1 2 ( 1 − f 1 0.1 + ( 1 − f 1 ) 2 cos ⁡ 2 ( 3 π f 1 ) ) f_{2}=\frac{1}{2}\left(1-f_{1}^{0.1}+(1-\sqrt{f_{1}})^{2} \cos ^{2}\left(3 \pi f_{1}\right)\right) f2=21(1f10.1+(1f1 )2cos2(3πf1))
POS:         x i = sin ⁡ ( 0.5 π x i ) , ∀ x i ∈ x II  x_{i}=\sin \left(0.5 \pi x_{i}\right), \forall x_{i} \in \mathbf{x}_{\text {II }} xi=sin(0.5πxi),xixII 

       Domain: [ 0 , 1 ] n [0,1]^{n} [0,1]n; Number of Variables = 30
       

F4:

                      f 1 ( x ) = ( 1 + g ( x ) ) ( x 1 x 2 x 3 ) f_{1}(x)=(1+g(x))\left(\frac{x_{1}}{\sqrt{x_{2} x_{3}}}\right) f1(x)=(1+g(x))(x2x3 x1)
                      f 2 ( x ) = ( 1 + g ( x ) ) ( x 2 x 1 x 3 ) f_{2}(x)=(1+g(x))\left(\frac{x_{2}}{\sqrt{x_{1} x_{3}}}\right) f2(x)=(1+g(x))(x1x3 x2)
                      f 3 ( x ) = ( 1 + g ( x ) ) ( x 3 x 1 x 2 ) f_{3}(x)=(1+g(x))\left(\frac{x_{3}}{\sqrt{x_{1} x_{2}}}\right) f3(x)=(1+g(x))(x1x2 x3)

where
                      g ( x ) = ∑ i = 4 n ( x i − 2 ) 2 g(x)=\sum_{i=4}^{n}\left(x_{i}-2\right)^{2} g(x)=i=4n(xi2)2
       

POF:        f 1 f 2 f 3 = 1 f_{1} f_{2} f_{3}=1 f1f2f3=1
POS:         x i = 2 , i = 3 , … , n x_{i}=2, i=3, \ldots, n xi=2,i=3,,n

       Domain: [ 1 , 4 ] n { {[1,4]}^{n}} [1,4]n; Number of Variables = 30
       

F5:

                      f 1 ( x ) = ( 1 + g ( x ) ) ( ( 1 − x 1 ) x 2 ) f_{1}(x)=(1+g(x))\left(\left(1-x_{1}\right) x_{2}\right) f1(x)=(1+g(x))((1x1)x2)
                      f 2 ( x ) = ( 1 + g ( x ) ) ( x 1 ( 1 − x 2 ) ) f_{2}(x)=(1+g(x))\left(x_{1}\left(1-x_{2}\right)\right) f2(x)=(1+g(x))(x1(1x2))
                      f 3 ( x ) = ( 1 + g ( x ) ) ( 1 − x 1 − x 2 + 2 x 1 x 2 ) 6 f_{3}(x)=(1+g(x))\left(1-x_{1}-x_{2}+2 x_{1} x_{2}\right)^{6} f3(x)=(1+g(x))(1x1x2+2x1x2)6

where
                      g ( x ) = ∑ i = 3 n ( x i − 0.5 ) 2 g(x)=\sum_{i=3}^{n}\left(x_{i}-0.5\right)^{2} g(x)=i=3n(xi0.5)2
       

POF:         f 3 = ( 1 − f 1 − f 2 ) 6 f_{3}=\left(1-f_{1}-f_{2}\right)^{6} f3=(1f1f2)6
POS:        x i = 0.5 , i = 3 , … , n x_{i}=0.5, i=3, \ldots, n xi=0.5,i=3,,n

       Domain: [ 0 , 1 ] n [0,1]^{n} [0,1]n; Number of Variables = 30
       

F6:

                      f 1 ( x ) = cos ⁡ 4 ( 0.5 π x 1 ) cos ⁡ 4 ( 0.5 π x 2 ) f_{1}(x)=\cos ^{4}\left(0.5 \pi x_{1}\right) \cos ^{4}\left(0.5 \pi x_{2}\right) f1(x)=cos4(0.5πx1)cos4(0.5πx2)
                      f 2 ( x ) = cos ⁡ 4 ( 0.5 π x 1 ) sin ⁡ 4 ( 0.5 π x 2 ) f_{2}(x)=\cos ^{4}\left(0.5 \pi x_{1}\right) \sin ^{4}\left(0.5 \pi x_{2}\right) f2(x)=cos4(0.5πx1)sin4(0.5πx2)
                      f 3 ( x ) = ( 1 + g ( x ) 1 + cos ⁡ 2 ( 0.5 π x 1 ) ) 1 1 + g ( x ) f_{3}(x)=\left(\frac{1+g(x)}{1+\cos ^{2}\left(0.5 \pi x_{1}\right)}\right)^{\frac{1}{1+g(x)}} f3(x)=(1+cos2(0.5πx1)1+g(x))1+g(x)1

where
                      g ( x ) = 1 10 ∑ i = 3 n ( 1 + x i 2 − cos ⁡ ( 2 π x i ) ) ) \left.g(x)=\frac{1}{10} \sum_{i=3}^{n}\left(1+x_{i}^{2}-\cos \left(2 \pi x_{i}\right)\right)\right) g(x)=101i=3n(1+xi2cos(2πxi)))
       

POF:         f 3 ( 1 + f 1 + f 2 ) = 1 f_{3}(1+\sqrt{f_{1}}+\sqrt{f_{2}})=1 f3(1+f1 +f2 )=1
POS:        x i = 0 , i = 3 , … , n x_{i}=0, i=3, \ldots, n xi=0,i=3,,n

       Domain: [ 0 , 1 ] n [0,1]^{n} [0,1]n; Number of Variables = 30

猜你喜欢

转载自blog.csdn.net/qq_43657442/article/details/108350257