新建python文件upload_py.py
from flask import Flask, render_template, request
from werkzeug.utils import secure_filename
import os
app = Flask(__name__)
app.config['MAX_CONTENT_PATH'] = 1024*1024 #指定最大文件大小，单位为字节
@app.route('/upload')
def upload_file():
return render_template('upload.html')
@app.route('/uploader', methods=['GET', 'POST'])
def upload_file1():
if request.method == 'POST':
f = request.files['file']
basepath = os.path.dirname(__file__) # 当前文件所在路径
print(basepath)
upload_path = os.path.join(basepath, 'file', secure_filename(f.filename))
# 注意：没有的文件夹一定要先创建，不然会提示没有该路径
print(upload_path)
upload_path = os.path.abspath(upload_path) # 将路径转换为绝对路径
print(upload_path)
f.save(upload_path)
return 'file uploaded successfully'
return render_template('upload.html')
if __name__ == '__main__':
app.run(debug=True)在py文件同级目录下新建templates/upload.html
<html>
<body>
<form action = "http://localhost:5000/uploader" method = "POST"
enctype = "multipart/form-data">
<input type = "file" name = "file" />
<input type = "submit"/>
</form>
</body>
</html>