Problem Description
S is a string of length n. S consists of lowercase English alphabets.
Your task is to count the number of different S with the minimum number of distinct sub-palindromes. Sub-palindrome is a palindromic substring.
Two sub-palindromes u and v are distinct if their lengths are different or for some i (0≤i≤length), ui≠vi. For example, string “aaaa” contains only 4 distinct sub-palindromes which are “a”, “aa”, “aaa” and “aaaa”.
Input
The first line contains an integer T (1≤T≤105), denoting the number of test cases.
The only line of each test case contains an integer n (1≤n≤109).
Output
For each test case, output a single line containing the number of different strings with minimum number of distinct sub-palindromes.
Since the answer can be huge, output it modulo 998244353.
Sample Input
2
1
2
Sample Output
26
676
题目大意:给定字符串的长度,求用最小数量的不同子回文串组成的串数目
题解:找规律,n=1,是26,n=2是676,n=3是17576,n大于3是15600
代码:
#include <stdio.h>
#include <string.h>
#include <iostream>
#include <queue>
using namespace std;
typedef long long ll;
int main()
{
int T;
cin>>T;
while(T--)
{
ll n;
cin>>n;
switch(n)
{
case 1:
cout<<26<<endl;
break;
case 2:
cout<<676<<endl;
break;
case 3:
cout<<17576<<endl;
break;
default:
cout<<15600<<endl;
break;
}
}
}