19、剑指offer - 顺时针打印矩阵

考点:

画图让抽象形象化

题目描述:

输入一个矩阵,按照从外向里以顺时针的顺序依次打印出每一个数字,例如,如果输入如下4 X 4矩阵: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 则依次打印出数字1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10.

解题:

class Solution {
public:
    vector<int> printMatrix(vector<vector<int> > matrix) {
        vector<int> res;
        int row = matrix.size();
        int col = matrix[0].size();
        if(row == 0 || col == 0){
            return res;
        }
        
        int top = 0;
        int right = col - 1;
        int bottom = row - 1;
        int left = 0;
        while(top <= bottom && left <= right){
            //left->right
            for(int i = left;i <= right;i++){
                res.push_back(matrix[top][i]);
            }
            top++;
            //top->bottom
            for(int i = top;i <= bottom;i++){
                res.push_back(matrix[i][right]);
            }
            right--;
            //最后剩下 只有一行或一列时,执行上面2个操作就已遍历完毕。
            if(top > bottom || left > right)
                return res;
            //right->left
            for(int i = right;i >= left;i--){
                res.push_back(matrix[bottom][i]);
            }
            bottom--;
            //bottom->top
            for(int i = bottom;i >= top;i--){
                res.push_back(matrix[i][left]);
            }
            left++;
        }
        return res;
    }
};
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转载自blog.csdn.net/qq_42250189/article/details/105608124