多级菜单展示(1)

如何将一个list中的对象按照父子菜单包含关系展示?

示例代码:

实体类:

import lombok.*;

import java.util.List;

@Setter
@Getter
@ToString
@NoArgsConstructor
@AllArgsConstructor
public class Menu {

    private int id;
    private int parentId;
    private String name;
    private List<Menu> children;


    public Menu(int id, int parentId, String name) {
        this.id = id;
        this.parentId = parentId;
        this.name = name;
    }
}

测试类:

import org.junit.Test;

import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

public class SimpleTest2 extends  BaseTest{

    @Test
    public void testListToMap(){

        List<Menu> menuList = new ArrayList<>();
        menuList.add(new Menu(1,0,"后台管理"));
        menuList.add(new Menu(2,1,"用户管理"));
        menuList.add(new Menu(3,1,"角色管理"));
        menuList.add(new Menu(4,1,"菜单管理"));
        menuList.add(new Menu(5,0,"商品管理"));
        menuList.add(new Menu(6,5,"商品查询"));
        menuList.add(new Menu(7,5,"商品添加"));

        Map<Integer,Menu> menus = new HashMap<>();

        //获取一级菜单,这里是后台管理,商品管理添加到menus里
        for(Menu menu: menuList){
            //parentId = 0 代表父菜单
            if(menu.getParentId() == 0){
                menus.put(menu.getId(),menu);
            }else{
                continue;
            }
        }


            // 加载二级菜单
            for(Menu menu:menuList){
                if(menu.getParentId() != 0 && menus.get(menu.getParentId()) != null){
                    //父节点
                    Menu parentNode = menus.get(menu.getParentId());
                    //子节点
                    Menu childNode  = menu;

                    if(parentNode.getChildren() == null){
                        List<Menu> children = new ArrayList<>();
                        parentNode.setChildren(children);
                    }
                    parentNode.getChildren().add(childNode);
                }

            }
             // 二级菜单加载完毕

        
              // 迭代打印菜单
        for(Integer id: menus.keySet()){
            Menu menu = menus.get(id);
            System.out.println(menu.getName());
            if(menu.getChildren() != null){
                for(Menu menu1: menu.getChildren()){
                    System.out.println("\t" + menu1.getName());

                }
            }
        }

    }

}

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转载自blog.csdn.net/weixin_43862596/article/details/102846701