python爬取两个excel表里的相同数据并匹配输出

import xlrd
def extract(inpath):
    data = xlrd.open_workbook(inpath, encoding_override='utf-8')
    table = data.sheets()[0]  # 选定表
    nrows = table.nrows  # 获取行号
    ncols = table.ncols  # 获取列号
    all_info =[]
    teacher = getnew(inpathnew)
    print(teacher)


   # print(nrows)
    for i in range(0, nrows):  # 第0行为表头
        if i == 10:
            break
        else:
            alldata = table.row_values(i)  # 循环输出excel表中每一行，即所有数据
            result = alldata[0] + '、' + alldata[1] + '、' + alldata[2] + '、' + alldata[3] + '、' + alldata[4]  # 取出表中第二列数据
            name = '刘诗诗'
            data = name in result
            if data:
                index = i
                same_name = name
        #print(result)



def getnew(inpathnew):
    data = xlrd.open_workbook(inpathnew, encoding_override='utf-8')
    table = data.sheets()[0]  # 选定表
    nrows = table.nrows  # 获取行号
    ncols = table.ncols  # 获取列号
    all_info =[]

    for i in range(1, nrows):  # 第0行为表头
        alldata = table.row_values(i)  # 循环输出excel表中每一行，即所有数据
        result = alldata
        #result = alldata[0] + '、' + alldata[1] + '、' + alldata[2] + '、' + alldata[3] + '、' + alldata[4] + '、' + alldata[5]  # 取出表中第二列数据
        all_info.append(result)
    print(all_info)

        #all_info = (2, 5, 8, 10, 8, 12, 23, 3, 2, 3, 5)
    import itertools
    original_list = all_info
    new_merged_list = list(itertools.chain(*original_list))
    print(new_merged_list)
    arr = new_merged_list
    print(arr)
    n = len(arr)
    for i in range(0, n):
        for j in range(i + 1, n):
            if (arr[i] == arr[j]):

                print("%s,%s" % (arr[i], arr[j]))

        # # 定义列表
        # l = ["a", "b", "c", "a", "b", "c", "a"]
        # # 获取第一个"a"的下标
        # index_one = l.index("a")
        # # 从第一个"a"的下一个位置开始查找, 所以加1
        # print(l.index("a", index_one + 1))

    #return all_info

inpath = ("111.xlsx")  # excel文件所在路径
inpathnew = ("222.xlsx")  # excel文件所在路径
#extract(inpath)
getnew(inpathnew)