Description
A string S
of lowercase letters is given. We want to partition this string into as many parts as possible so that each letter appears in at most one part, and return a list of integers representing the size of these parts.
Example 1:
Input: S = "ababcbacadefegdehijhklij" Output: [9,7,8] Explanation: The partition is "ababcbaca", "defegde", "hijhklij". This is a partition so that each letter appears in at most one part. A partition like "ababcbacadefegde", "hijhklij" is incorrect, because it splits S into less parts.
Note:
S
will have length in range[1, 500]
.S
will consist of lowercase letters ('a'
to'z'
) only.
class Solution { public: vector<int> partitionLabels(string S) { int len = 0,m=0; vector<int>sum; map<char,int>mp; int i=0; while (i<S.length()) { len++; for (; i < len; i++) { if (!mp.count(S[i])) { mp[S[i]] = 0; for (int j = S.length() - 1; j >= i; j--) { if (S[i] == S[j]) { if (len <= j) len = j + 1; break; } } } } sum.push_back(len - m); m = len; } return sum; } };