python中给定两个列表,怎么找出他们相同的元素和不同的元素?

如列表a和列表b,则相同元素为1,不同元素为2,3,4,5,6

a = [1, 2, 3, 4]

b = [1, 5, 6]

1. 位运算
print(set(a) & set(b))

print(set(a) ^ set(b)) # 异或

2. 列表推导式
same = [x for x in a if x in b]

print(same)

diff = [y for y in (a + b) if y not in same]

print(diff)

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转载自www.cnblogs.com/newlangwen/p/12668783.html