人民币小写转换为大写

今天在超市，忽然想到可以写一段代码实现当收银员输入阿拉伯数字的人民币时，能够以规范的大写形式将其自动打印到发票上。

注：转换规范如下示例：
（1） 100000010100.09
人民币壹仟亿零壹万零壹佰元零角玖分
（2） 123456789.00
人民币壹亿贰仟叁佰肆拾伍万陆仟柒佰捌拾玖元整
（3） 1000000000.09
人民币拾亿元零角玖分
以下是我使用java实现该功能的代码：

import java.util.Scanner;

public class RMBSwitch {

    public static void main(String[] args){
        System.out.println("please input a double number");
        Scanner scanner=new Scanner(System.in);//最多允许输入：左边12位，右边必须两位
        String RMBArabic=scanner.next();        
        String RMBCN="人民币";
        String[] totalInput=RMBArabic.split("\\.");
        System.out.println("The result is");
        System.out.println(RMBCN+leftToCN(totalInput[0])+rightToCN(totalInput[1]));
        scanner.close();
    }

    //转换左边整数部分
    public static String leftToCN(String left){
        String leftCN="";
        String[] ZHCN={"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};        
        String[] unitCN={"","拾","佰","仟"};

        if (left.length()<=4) {
            for (int i = 0; i < left.length(); i++) {
                leftCN=leftCN+ZHCN[Integer.valueOf(left.charAt(i))-48]+unitCN[left.length()-i-1];
            }
            leftCN=leftCN+"元";
        }

        if (left.length()<=8&&left.length()>4) {
            for (int i = 0; i < left.length()-4; i++) {
                leftCN=leftCN+ZHCN[Integer.valueOf(left.charAt(i))-48]+unitCN[left.length()-i-5];
            }
            leftCN=leftCN+"万";

            for (int i = left.length()-4; i < left.length(); i++) {
                leftCN=leftCN+ZHCN[Integer.valueOf(left.charAt(i))-48]+unitCN[left.length()-i-1];
            }
            leftCN=leftCN+"元";
        }

        if (left.length()<=13&&left.length()>8) {
            for (int i = 0; i < left.length()-8; i++) {
                leftCN=leftCN+ZHCN[Integer.valueOf(left.charAt(i))-48]+unitCN[left.length()-i-9];
            }
            leftCN=leftCN+"亿";

            for (int i = left.length()-8; i < left.length()-4; i++) {
                leftCN=leftCN+ZHCN[Integer.valueOf(left.charAt(i))-48]+unitCN[left.length()-i-5];
            }
            leftCN=leftCN+"万";

            for (int i = left.length()-4; i < left.length(); i++) {
                leftCN=leftCN+ZHCN[Integer.valueOf(left.charAt(i))-48]+unitCN[left.length()-i-1];
            }
            leftCN=leftCN+"元";
        }

        if (leftCN.charAt(0)=='壹'&&leftCN.charAt(1)=='拾') {
            leftCN=leftCN.substring(1);
        }       

        while(scanString(leftCN)==1){
            for (int i = 0; i < leftCN.length()-1; i++) {
                if (leftCN.charAt(i)=='零'&&(leftCN.charAt(i+1)=='亿'||leftCN.charAt(i+1)=='万')) {
                    leftCN=leftCN.substring(0, i)+leftCN.substring(i+1);
                }
                if (leftCN.charAt(i)=='零'&&(leftCN.charAt(i+1)=='拾'||leftCN.charAt(i+1)=='佰'||leftCN.charAt(i+1)=='仟'||leftCN.charAt(i+1)=='元'||leftCN.charAt(i+1)=='零')) {
                    leftCN=leftCN.substring(0, i+1)+leftCN.substring(i+2);
                }
            }
        }

        if (leftCN.charAt(leftCN.length()-1)=='零') {
            leftCN=leftCN.substring(0,leftCN.length()-1)+"元";
        }

        if (leftCN.charAt(leftCN.indexOf('万')-1)=='亿') {
            leftCN=leftCN.substring(0,leftCN.indexOf('万'))+leftCN.substring(leftCN.indexOf('万')+1);
        }

        return leftCN;
    }

    public static int scanString(String stringIn){
        int flag=0;
        for (int i = 0; i < stringIn.length()-1; i++) {
            if (stringIn.charAt(i)=='零'&&(stringIn.charAt(i+1)=='万'||stringIn.charAt(i+1)=='亿')) {
                flag=1;
                break;
            }
            if (stringIn.charAt(i)=='零'&&(stringIn.charAt(i+1)=='拾'||stringIn.charAt(i+1)=='佰'||stringIn.charAt(i+1)=='仟'||stringIn.charAt(i+1)=='元'||stringIn.charAt(i+1)=='零')) {
                flag=1;
                break;
            }
        }

        return flag;
    }

    //转换右边小数部分
    public static String rightToCN(String right){
        String[] ZHCN={"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};
        String rightCN="";
        if (right.charAt(0)=='0'&&right.charAt(1)=='0') {
            rightCN=rightCN+"整";
        }else {
            rightCN=rightCN+ZHCN[Integer.valueOf(right.charAt(0))-48]+"角"+ZHCN[Integer.valueOf(right.charAt(1))-48]+"分";
        }
        return rightCN;
    }

}

我的实现思路为：先将其全部读出来，不考虑多个零或者单个零的情况，然后再处理读出来的字符串中的零，如果谁有更好的方法可以在评论区留言，谢谢！

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