hdu 1754 I Hate It 解题报告 线段树
解题思路:线段树。线段树是树状数组的升级版,能进行区间查询,而树状数组只能使用前缀,但是树状数组编写简单。
#include<iostream>
#include<math.h>
#include<iomanip>
#include<algorithm>
#include<queue>
#include<cstring>
#include<string>
#include<string.h>
#include<map>
#include<stack>
#include<stdio.h>
#include<cstdio>
#include<stdlib.h>
#include<fstream>
#include<sstream>
#include<set>
#pragma warning(disable:4996)
#define INF 0x3f3f3f3f
#define ll long long
#define PI acos(-1.0)
const int N = 100005;
const int maxn = 1e9;
using namespace std;
int n, m;
int a[200005];
int tree[800020];//tree里放区间中的最大值
void build(int id, int l, int r)
{
if (l == r)
{
tree[id] = a[l];
return;
}
int mid = (l + r) >> 1;
build(id << 1, l, mid);
build(id << 1 | 1, mid + 1, r);
tree[id] = max(tree[id << 1], tree[id << 1 | 1]);
}
int query(int id,int l,int r,int x,int y)
{
if (x <= l && y >= r)
{
return tree[id];
}
int mid = (l + r) >> 1;
int mx = -1 << 30;//初始为负无穷
if (x <= mid)
mx = max(mx, query(id << 1, l, mid, x, y));
if (y > mid)
mx = max(mx, query(id << 1 | 1, mid + 1, r, x, y));
return mx;
}
void update(int id, int l, int r, int x, int y)
{
if (l == r)
{
tree[id] = y;
return;
}
int mid = (l + r) >> 1;
if (x <= mid)
update(id << 1, l, mid, x, y);
else
update(id << 1 | 1, mid + 1, r, x, y);
tree[id] = max(tree[id << 1], tree[id << 1 | 1]);
}
int main()
{
while (scanf("%d%d",&n,&m)!=EOF)
{
memset(a, 0, sizeof(a));
for (int i = 1; i <= n; i++)
{
scanf("%d", &a[i]);
}
build(1, 1, n);
while (m--)
{
char ch;
int x, y;
scanf(" %c%d%d", &ch, &x, &y);//注意%c前面要留空格将上一行键入的回车消除
if (ch == 'Q')
printf("%d\n", query(1, 1, n, x, y));
else
update(1, 1, n, x, y);
}
}
}