6-2-Two Stacks In One Array-函数题

6-2-Two Stacks In One Array-函数题

解题代码

Stack CreateStack(int MaxElements) {
	Stack new = (Stack)malloc(sizeof(struct StackRecord));
	new->Capacity = MaxElements;
	new->Top1 = -1;
	new->Top2 = new->Capacity;
	new->Array = (ElementType *)malloc(MaxElements * sizeof(ElementType));
    return new;
}
int IsEmpty(Stack S, int Stacknum) {
	if (Stacknum == 1) {
		if (S->Top1 == -1) return 1;
		else return 0;
	}
	else {
		if (S->Top2 == S->Capacity) return 1;
		else return 0;
	}
}
int IsFull(Stack S) {
	if (S->Top2 - S->Top1 == 1) return 1;
	else return 0;
}
int Push(ElementType X, Stack S, int Stacknum) {
	if (!IsFull(S)) {
		if (Stacknum == 1) {
			S->Array[++S->Top1] = X;
			return 1;
		}
		else {
			S->Array[--S->Top2] = X;
			return 1;
		}
	}
	else {
		return 0;
	}
}
ElementType Top_Pop(Stack S, int Stacknum) {
	if (!IsEmpty(S, Stacknum)) {
		if (Stacknum == 1) {
			return S->Array[S->Top1--];
		}
		else {
			return S->Array[S->Top2++];
		}
	}
	else {
		return ERROR;
	}
}

测试结果

在这里插入图片描述

问题整理

1.这题海星。
发布了47 篇原创文章 · 获赞 2 · 访问量 1335

猜你喜欢

转载自blog.csdn.net/Aruasg/article/details/105158537