千锋20200306

在千锋“逆战”学习第25天

      每日一句:程序员是值得尊敬的,程序员的双手是魔术师的双手,他们把枯燥无味的代码变成了丰富多彩的软件。
      今天学习了Map集合相关内容
      下周继续努力。

作业

4.有如下代码:

public class TestListSet {
	public static void main(String[] args) {
		List<String> list = new ArrayList<String>();
		list.add("Hello");
		list.add("Learn");
		list.add("Hello");
		list.add("Welcome");
		Set<String> set = new HashSet<String>();
		set.addAll(list);
		System.out.println(set.size());
	}
}

运行结果:

编译运行都正常,输出3

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6.为第5题的worker类,在添加完equals方法的基础上,添加一个hashCode方法

public int hashCode(){
//1
}
(1)	return 0;
(2)	int result = 0;
if(name!=null) result = name.hashCode();
return result + age;
(3)	return super.hashCode();
现在要把Worker类放入HashSet中,并希望HashSet中没有重复元素,则
(1)(2)写法正确,(2)效率更高

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7.代码改错

class Worker {
	String name;
	int age;
	double salary;

	public Worker() {
	}

	public Worker(String name, int age, double salary) {
		this.name = name;
		this.age = age;
		this.salary = salary;
	}

	int hashCode() {
		return name.hashCode() + age + salary;
	}

	public boolean equals(Worker w) {
		if (w.name == name && w.salary == salary && w.age == age) {
			return true;
		} else {
			return false;
		}
	}
}

public class TestWorker {
	public static void main(String[] args) {
		Set<Worker> set = new HashSet<Worker>();
		set.add(new Worker("tom", 18, 2000));
		set.add(new Worker("tom", 18, 2000));
		set.add(0,new Worker("jerry", 18, 2000));
		System.out.println(set.size());
	}
}
//1 重写父类方法,权限不能小于父类;salary是double类型,返回值要强转为int型
public int hashCode() {
		return (int) (name.hashCode() + age + salary);
	} 
//2 HashSet是无序的集合,不能在指定位置添加
set.add(new Worker("jerry", 18, 2000));

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8.在前面Worker类的基础上,为Worker类添加相应的方法,使得Worker放入HashSet中时,Set中没有重复元素。并编写相应的测试代码。

public class Worker {
	private String name;
	private Integer age;
	private Integer salary;

	public Worker() {
	}

	public Worker(String name, int age, Integer salary) {
		this.name = name;
		this.age = age;
		this.salary = salary;
	}

	public String getName() {
		return name;
	}

	public void setName(String name) {
		this.name = name;
	}

	public int getAge() {
		return age;
	}

	public void setAge(int age) {
		this.age = age;
	}

	public double getSalary() {
		return salary;
	}

	public void setSalary(Integer salary) {
		this.salary = salary;
	}

	public void work() {
		System.out.println(name + " work");
	}

	public String toString() {
		return "Worker [name=" + name + ", age=" + age + ", salary=" + salary + "]";
	}

	// 为worker类添加equals方法
	public boolean equals(Object obj) {
		if (this == obj) {
			return true;
		}
		if (obj == null) {
			return false;
		}
		if (this.getClass() != obj.getClass()) {
			return true;
		}
		Worker worker = (Worker) obj;
		if (this.name.equals(worker.name) && this.age == worker.age && this.salary == worker.salary) {
			return true;
		}
		return false;
	}
	public int hashCode() {
		final int prime = 31;
		int result = 1;
		result = prime * result + ((age == null) ? 0 : age.hashCode());
		result = prime * result + ((name == null) ? 0 : name.hashCode());
		result = prime * result + ((salary == null) ? 0 : salary.hashCode());
		return result;
	}
}
public class TestWorker {
	public static void main(String[] args) {

		HashSet<Worker> set = new HashSet<>();

		Worker wor1 = new Worker("zhang3", 18, 3000);
		Worker wor2 = new Worker("li4", 25, 3500);
		Worker wor3 = new Worker("wang5", 22, 3200);
		Worker wor4 = new Worker("zhao6", 24, 3300);
		Worker wor5 = new Worker("wang5", 22, 3200);

		set.add(wor1);
		set.add(wor2);
		set.add(wor3);
		set.add(wor4);
		set.add(wor5);
		System.out.println(set.size() + "个元素");
		Iterator<Worker> it = set.iterator();
		while (it.hasNext()) {
			System.out.println(it.next());
		}
	}
}

运行结果:

5个元素
Worker [name=zhao6, age=24, salary=3300]
Worker [name=wang5, age=22, salary=3200]
Worker [name=wang5, age=22, salary=3200]
Worker [name=zhang3, age=18, salary=3000]
Worker [name=li4, age=25, salary=3500]

--------------------------------------------------------------------------

在这里插入图片描述

--------------------------------------------------------------------------
10.利用Map完成以下功能 从命令行读取一个字符串,表示一个年份,输出该年世界杯冠军是哪支球队。如果该年没有举办世界杯,则输出:没有举办世界杯

public class TestWorldCup {
	public static void main(String[] args) {
		Map<String, String> map = new HashMap<String, String>();
		map.put("2006", "意大利");
		map.put("2002", "巴西");
		map.put("1998", "法国");
		map.put("1994", "巴西");
		map.put("1990", "德国");
		map.put("1986", "阿根廷");
		map.put("1982", "意大利");
		map.put("1978", "阿根廷");
		map.put("1974", "德国");
		map.put("1970", "巴西");
		map.put("1966", "英格兰");
		map.put("1962", "巴西");
		map.put("1958", "巴西");
		map.put("1954", "德国");
		map.put("1950", "乌拉圭");
		map.put("1938", "意大利");
		map.put("1934", "意大利");
		map.put("1930", "乌拉圭");

		Scanner input = new Scanner(System.in);
		System.out.print("输入一个年份:");
		String str = input.next();
		if (map.containsKey(str)) {
			System.out.println("该年世界杯冠军是:" + map.get(str));
		} else {
			System.out.println("没有举办世界杯");
		}
	}
}

运行结果:

输入一个年份:1970
该年世界杯冠军是:巴西

输入一个年份:1996
没有举办世界杯

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11.已知某学校课程安排
      (1)使用Map,以老师名字作为键,教授的课程名作为值,表示上述课程安排
      (2)增加一位新教师Allen教JDBC
      (3)Lucy改为教CoreJava
      (4)遍历Map,输出所有老师及老师教授的课程
      (5)利用Map,输出所有教JSP的老师

public class TestMap {
	public static void main(String[] args) {
		Map<String,String> map = new HashMap<String, String>();
		//1.使用Map,以老师名字作为键,教授的课程名作为值,表示上述课程安排
		map.put("Tom","CoreJava");
		map.put("John","Oracle");
		map.put("Susan","Oracle");
		map.put("Jerry","JDBC");
		map.put("Jim","Unix");
		map.put("Kevin","JSP");
		map.put("Lucy","JSP");
		//2.增加一位新教师Allen教JDBC
		map.put("Allen", "JDBC");
		//3.Lucy改为教CoreJava
		map.put("Lucy", "CoreJava");
		//4.输出所有老师及老师教授的课程
		Set<String> keySet = map.keySet();
		Iterator<String> iterator = keySet.iterator();
		System.out.println("老师"+"\t"+"课程");
        while (iterator.hasNext()) {
            String key = (String) iterator.next();
            System.out.println(key+"\t"+map.get(key));
        }
        //5.输出所有教JSP的老师
        System.out.println("教JSP的老师");
        for(String key:keySet) {
        	if(map.get(key).equals("JSP")) {
        		System.out.println(key);
        	}
        }
	}
}

运行结果:

老师	课程
Kevin	JSP
Tom	CoreJava
Susan	Oracle
John	Oracle
Lucy	CoreJava
Jerry	JDBC
Allen	JDBC
Jim	Unix
教JSP的老师
Kevin

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12.有如下代码:

class Student {
	String name;
	int age;

	public Student() {
	}

	public Student(String name, int age) {
		this.name = name;
		this.age = age;
	}

	public int hashCode() {
		return name.hashCode() + age;
	}

	public boolean equals(Object o) {
		if (o == null)
			return false;
		if (o == this)
			return true;
		if (o.getClass() != this.getClass())
			return false;
		Student stu = (Student) o;
		if (stu.name.equals(name) && stu.age == age)
			return true;
		else
			return false;
	}
}

public class TestHashSet {
	public static void main(String[] args) {
		Set<Student> set = new HashSet<Student>();
		Student stu1 = new Student();
		Student stu2 = new Student("Tom", 18);
		Student stu3 = new Student("Tom", 18);
		set.add(stu1);
		set.add(stu2);
		set.add(stu3);
		System.out.println(set.size());
	}
}

运行结果:

编译正确,运行时异常,空指针异常

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13.在原有世界杯Map的基础上,增加如下功能
      读入一支球队的名字,输出该球队夺冠的年份列表

Scanner input = new Scanner(System.in);
		System.out.print("输入一个球队:");
		String str = input.nextLine();
		if (map.containsValue(str)) {
			for (String s : map.keySet()) {
				if (map.get(s).contains(str)) {
					System.out.println(s + "\t");
				}
			}
		} else {
			System.out.println("该球队没有获得过世界杯");
		}
	}
}

运行结果:

输入一个球队:巴西
1962	
1994	
1970	
2002	
1958

输入一个球队:中国
该球队没有获得过世界杯

--------------------------------------------------------------------------
14.给定一个字符串,输出该字符串由哪些字符组成,每个字符出现多少次

public class Test {
	public static void main(String[] args) {
		LetterCount test = new LetterCount();
		test.countChar("aaabbcd985ABBbb789");
	}
}

class LetterCount {
	private Map<Character, Integer> countMap = new HashMap<Character, Integer>();
	public void countChar(String str) {
		char[] chars = str.toCharArray();
		for (char ch : chars) {
			if (!countMap.containsKey(ch)) {
				countMap.put(ch, 0);
			}
			int count = countMap.get(ch);
			countMap.put(ch, count + 1);
		}
		Set<Character> keys = countMap.keySet();
		for (Character ch : keys) {
			System.out.println("字符" + ch + "出现次数:" + countMap.get(ch));
		}
	}
}

运行结果:

字符a出现次数:3
字符A出现次数:1
字符b出现次数:4
字符B出现次数:2
字符c出现次数:1
字符d出现次数:1
字符5出现次数:1
字符7出现次数:1
字符8出现次数:2
字符9出现次数:2
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