Python的进度条显示

1.终端进度条显示:

# -*- coding: utf-8 -*-#
# Author:       weiz
# Date:         2019/11/26 10:22
# Name:         main
# Description:
import time
from progressbar import ProgressBar, Percentage, Bar, RotatingMarker, ETA, FileTransferSpeed

total = 1000
# 1.基本用法
progress = ProgressBar()

## 1.1第一种用法
for i in progress(range(total)):
    time.sleep(0.01)

## 1.2第二种用法
pbar = ProgressBar().start()
for i in range(1, 1000):
    pbar.update(int((i/(total-1))*100))
    time.sleep(0.01)
pbar.finish()


# 2.高级用法
widgets = ["Progress:", Percentage(), ' ', Bar(marker=RotatingMarker('>-=')), ' ', ETA(), ' ', FileTransferSpeed()]
pbar = ProgressBar(widgets=widgets, maxval=1000000).start()
for i in range(100000):
    # do somethimg
    pbar.update(10*i + 1)
    time.sleep(0.0001)
pbar.finish()

在ubuntu上的pycharm好像不行,不会显示进度,只会一下全部显示进度;在ubuntu终端效果如下:

封装成类:

# -*- coding: utf-8 -*-#
# Author:       weiz
# Date:         2019/11/26 10:22
# Name:         main
# Description:
import sys
import time

class ShowProcess():
    """
    显示处理进度的类
    调用该类相关函数即可实现处理进度的显示
    """
    i = 0 # 当前的处理进度
    max_steps = 0 # 总共需要处理的次数
    max_arrow = 50 #进度条的长度
    infoDone = 'done'

    # 初始化函数,需要知道总共的处理次数
    def __init__(self, max_steps, infoDone = 'Done'):
        self.max_steps = max_steps
        self.i = 0
        self.infoDone = infoDone

    # 显示函数,根据当前的处理进度i显示进度
    # 效果为[>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>]100.00%
    def show_process(self, i=None):
        if i is not None:
            self.i = i
        else:
            self.i += 1
        num_arrow = int(self.i * self.max_arrow / self.max_steps) #计算显示多少个'>'
        num_line = self.max_arrow - num_arrow #计算显示多少个'-'
        percent = self.i * 100.0 / self.max_steps #计算完成进度,格式为xx.xx%
        process_bar = '[' + '>' * num_arrow + '-' * num_line + ']'\
                      + '%.2f' % percent + '%' + '\r' #带输出的字符串,'\r'表示不换行回到最左边
        sys.stdout.write(process_bar) #这两句打印字符到终端
        sys.stdout.flush()
        if self.i >= self.max_steps:
            self.close()

    def close(self):
        print('')
        print(self.infoDone)
        self.i = 0

if __name__=='__main__':
    max_steps = 100

    process_bar = ShowProcess(max_steps, 'OK')

    for i in range(max_steps):
        process_bar.show_process()
        time.sleep(0.1)

2.在pycharm和终端都可以显示进度

# -*- coding: utf-8 -*-#
# Author:       weiz
# Date:         2019/11/26 10:22
# Name:         main
# Description:
import sys
import time

progressBarTarget = 1000      # 现在只需要根据任务更改progressBarTarget就行
degree_of_completion = 0
for data in range(progressBarTarget):
    time.sleep(0.01)
    degree_of_completion += 1
    done = int(50 * degree_of_completion / progressBarTarget)
    sys.stdout.write("\r[%s%s] %d%%" % ('█' * done, ' ' * (50 - done), 100/progressBarTarget*degree_of_completion))
    sys.stdout.flush()
print()

完善一下,封装成类:

import sys
import time

class ShowProgressBar(object):
    def __init__(self, max_steps, step=1, infoDone='Done'):
        self.progressBarTarget = max_steps
        self.degree_of_completion = 0
        self.infoDone = infoDone
        self.step = step

    # 显示函数
    def show_process(self, step=None):
        if step is not None:
            self.step = step
        self.degree_of_completion += self.step
        done = int(50 * self.degree_of_completion / self.progressBarTarget)
        sys.stdout.write(
            "\r[%s%s] %d%%" % ('█' * done, ' ' * (50 - done), 100 / self.progressBarTarget * self.degree_of_completion))
        sys.stdout.flush()
        if self.degree_of_completion >= self.progressBarTarget:
            self.close()

    def close(self):
        print()
        print(self.infoDone)
        self.degree_of_completion = 0


if __name__ == "__main__":
    max_step = 1200
    p1 = ShowProgressBar(max_step)
    for i in range(max_step):
        time.sleep(0.01)
        if i % 10 == 0:
            p1.show_process(10)

    p2 = ShowProgressBar(100, infoDone="ok")
    for i in range(100):
        time.sleep(0.01)
        p2.show_process()

效果图:

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转载自blog.csdn.net/qq_31112205/article/details/103472971