Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where −10
6
≤a,b≤10
6
. The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input:
-1000000 9
Sample Output:
-999,991
题意:
题目大概意思是计算A+B的和，然后以每三位输出一个分隔逗号
思路:
先计算出来a+b，然后如果是负数，先把－号输出，然后把和变为正数，然后再转为字符串，遍历字符串，根据(i+1)%3==len%3&&i!=len-1输出逗号。
C++代码:
#include<cstdio>
#include<iostream>
#include<string>
using namespace std;
int main(){
int a,b,sum;
cin>>a>>b;
sum=a+b;
if(sum<0){
cout<<"-";
sum=-sum;
}
string s=to_string(sum);
int len=s.length();
for(int i=0;i<len;i++){
cout<<s[i];
if((i+1)%3==len%3&&i!=len-1){
cout<<',';
}
}
return 0;
}
