用Python算带有进度条的圆周率

from math import*
from time import*
scale=20
s,m,=1,2
print("执行开始".center(scale//2, "-"))
start = perf_counter()
for i in range(scale+1):
s=sqrt((1-sqrt(1-pow(s,2)))/2)
m=m*2
a = '*' * i
b = '.' * (scale - i)
c = (i/scale)*100
dur = perf_counter() - start
print("\r{:^3.0f}%[{}->{}]{:.2f}s".format(c,a,b,dur))
sleep(0.1)
Pi=s*m
print("Pi值是{}".format(Pi))
print("\n"+"执行结束".center(scale//2,'-'))