python编程:从入门到实践-7用户输入和while循环

1函数 input()的工作原理
让程序暂停运行,等待用户输入一些文本。获取用户输入后,Python将其存储在一个变量中

1.1编写清晰的程序
有时候,提示可能超过一行,例如,你可能需要指出获取特定输入的原因。在这种情况下,可将提示存储在一个变量中,再将该变量传递给函数input()

prompt = "If you tell us who you are, we can personalize the messages you see."
prompt += "\nWhat is your first name? "
name = input(prompt)
print("\nHello, " + name + "!")

If you tell us who you are, we can personalize the messages you see.
What is your first name? Eric
Hello, Eric!

1.2使用 int()来获取数值输入

1.3求模运算符(%)
将两个数相除并返回余数

6 % 3
0
7 % 3
1

1.4在 Python 2.7 中获取输入

2while 循环简介
2.1使用 while 循环

2.2让用户选择何时退出

2.3使用标志
在更复杂的程序中,很多不同的事件都会导致程序停止运行;在这种情况下,该怎么办呢?
导致程序结束的事件有很多时,如果在一条while语句中检查所有这些条件,将既复杂又困难。
在要求很多条件都满足才继续运行的程序中,可定义一个变量,用于判断整个程序是否处于活动状态。这个变量被称为标志,充当了程序的交通信号灯。你可让程序在标志为True时继续运行,并在任何事件导致标志的值为False时让程序停止运行。这样,在while语句中就只需检查一个条件——标志的当前值是否为True,并将所有测试(是否发生了应将标志设置为False的事件)都放在其他地方,从而让程序变得更为整洁

prompt = "\nTell me something, and I will repeat it back to you:"
prompt += "\nEnter 'quit' to end the program. "
active = True
while active:
    message = input(prompt)
    if message == 'quit':
        active = False
    else:
        print(message)

2.4使用 break 退出循环

prompt = "\nPlease enter the name of a city you have visited:"
prompt += "\n(Enter 'quit' when you are finished.) "
while True:
    city = input(prompt)
    if city == 'quit':
        break
    else:
        print("I'd love to go to " + city.title() + "!")

Please enter the name of a city you have visited:
(Enter 'quit' when you are finished.) New York
I'd love to go to New York!
Please enter the name of a city you have visited:
(Enter 'quit' when you are finished.) San Francisco
I'd love to go to San Francisco!
Please enter the name of a city you have visited:
(Enter 'quit' when you are finished.) quit

2.5在循环中使用 continue
返回到循环开头,并根据条件测试结果决定是否继续执行循环

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current_number = 0
while current_number < 10:
    current_number += 1
    if current_number % 2 == 0:
        continue
    print(current_number)

1
3
5
7
9

2.6避免无限循环

x = 1
while x <= 5:
    print(x)
    x += 1

如果程序陷入无限循环,可按Ctrl + C,也可关闭显示程序输出的终端窗口

3使用 while 循环来处理列表和字典
for循环是一种遍历列表的有效方式,但在for循环中不应修改列表,否则将导致Python难以跟踪其中的元素。要在遍历列表的同时对其进行修改,可使用while循环。通过将while循环同列表和字典结合起来使用,可收集、存储并组织大量输入,供以后查看和显示

3.1在列表之间移动元素
假设有一个列表,其中包含新注册但还未验证的网站用户;验证这些用户后,如何将他们移到另一个已验证用户列表中呢?
一种办法是使用一个while循环,在验证用户的同时将其从未验证用户列表中提取出来,再将其加入到另一个已验证用户列表中。

# 首先,创建一个待验证用户列表
# 和一个用于存储已验证用户的空列表
unconfirmed_users = ['alice', 'brian', 'candace']
confirmed_users = []
# 验证每个用户,直到没有未验证用户为止
# 将每个经过验证的列表都移到已验证用户列表中
while unconfirmed_users:
    current_user = unconfirmed_users.pop()
    print("Verifying user: " + current_user.title())
    confirmed_users.append(current_user)

# 显示所有已验证的用户
print("\nThe following users have been confirmed:")
for confirmed_user in confirmed_users:
    print(confirmed_user.title())

Verifying user: Candace
Verifying user: Brian
Verifying user: Alice
The following users have been confirmed:
Candace
Brian
Alice

3.2删除包含特定值的所有列表元素

pets = ['dog', 'cat', 'dog', 'goldfish', 'cat', 'rabbit', 'cat']
while 'cat' in pets:
    pets.remove('cat')
print(pets)

['dog', 'dog', 'goldfish', 'rabbit']

3.3使用用户输入来填充字典

responses = {}

# 设置一个标志,指出调查是否继续
polling_active = True

while polling_active:
# 提示输入被调查者的名字和回答
    name = input("\nWhat is your name? ")
    response = input("Which mountain would you like to climb someday? ")

    # 将答卷存储在字典中
    responses[name] = response
    
    # 看看是否还有人要参与调查
    repeat = input("Would you like to let another person respond? (yes/ no) ")
    if repeat == 'no':
    polling_active = False

# 调查结束,显示结果
print("\n--- Poll Results ---")
for name, response in responses.items():
    print(name + " would like to climb " + response + ".")

What is your name? Eric
Which mountain would you like to climb someday? Denali
Would you like to let another person respond? (yes/ no) yes
What is your name? Lynn
Which mountain would you like to climb someday? Devil's Thumb
Would you like to let another person respond? (yes/ no) no
--- Poll Results ---
Lynn would like to climb Devil's Thumb.
Eric would like to climb Denali.
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转载自blog.csdn.net/hehe20190825/article/details/105013791
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