3 つの数値の最も近い合計 - LeetCode

トピック:

問題解決のアイデア:

コード:

fun threeSumClosest(nums: IntArray, target: Int): Int {
    nums.sort() // 从小到大排序
    var result = 100000 // 超过最大值被减的时候就是最小值
    for (first in 0 until nums.size) {
        if (first > 0 && nums[first] == nums[first - 1]) {
            continue
        }
        var second = first + 1
        var third = nums.size - 1
        while (third > second) {
            val sum = nums[first] + nums[second] + nums[third]
            if (sum == target) {
                return target
            }
            if (abs(target - sum) < abs(target - result)) {
                result = sum
            }
            if (sum > target) {
                third--
                while (nums[third] == nums[third + 1] && third > second) {
                    third--
                }
            } else {
                second++
                while (nums[second] == nums[second - 1] && second < third) {
                    second++
                }
            }
        }
    }
    return result
}

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転載: blog.csdn.net/m0_37707561/article/details/128547587