During data processing, sometimes we need to output the difference of two tables for the next step of processing. Suppose
, now there are two tables table01.xlsx and table02.xlsx, and the difference between the "filename" column The sets are output to the other two tables respectively.
table01: 
table02:
overall idea:
output the elements in the two columns as list1 and list2 respectively—transform into sets set1 and set2—use the s1.difference(s2) method to find the difference set—convert the difference set into a list— —Create a new excel—list nested dictionary and convert it into a dataframe format and save it in the newly created excel.
The code is as follows:
import pandas as pd
import os
os.chdir("E:\\origin_file")
#1.读取表1的filename列
data1=pd.read_excel('table01.xlsx')
col1=data1.iloc[:,0] #目标字段在table01表格第一列，列序号为0
#或col1=data1['filename']
#2.将table01的“filename”列的元素加入到新建列表中
list1=[] #新建列表list1
for i1 in col1:
list1.append(i1)
#3.读取表2的filename列
data2=pd.read_excel("table02.xlsx")
col2=data2.iloc[:,0] #目标字段在table02表格第一列，列序号为0
#或col2=data2['filename']
#4.将table02的“filename”列的元素加入到新建列表中
list2=[] #新建列表list2
for i2 in col2:
list2.append(i2)
#5.将list1和list2分别转化为集合
set1=set(list1)
set2=set(list2)
#6.取set1和set2的差集
set3=set1.difference(set2) #table01有table02没有
set4=set2.difference(set1) #table02有table01没有
#7.差集转化为列表
list3=list(set3) #table01有table02没有
list4=list(set4) #table02有table01没有
#8.为两个差集分别建立excel
#table01有table02没有的元素建立的excel
writer1=pd.ExcelWriter('table01-02.xlsx')
#为table02有table01没有的元素建立的excel
writer2=pd.ExcelWriter('table02-01.xlsx')
#9.将两个差集列表分别嵌套字典
dict_1={
'filename':list3} #table01有table02没有
dict_2={
'filename':list4} #table02有table01没有
#10.将两个字典分别转化为dataframe格式
df1=pd.DataFrame(dict_1)
df2=pd.DataFrame(dict_2)
#11.分别将两个dataframe格式的差集储存到excel中
#table01有table02没有
df1.to_excel(writer1,'sheet1',startcol=0,index=False)
#table02有table01没有
df2.to_excel(writer2,'sheet2',startcol=0,index=False)
#12.保存两个excel文件
writer1.save()
writer2.save()
The results are as follows:
table01-02:
table02-01:
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