Use python bulk of output excel sheet name

Reuse this script to read excel in bulk and get the output of all excel sheet to a name of each file.

Environment: python 3.7.3

. 1  # - * - Coding: UTF-. 8 - * - 
2  
. 3  '' ' 
. 4  purpose of this is to obtain a plurality of code sheet excl of name, and output to the specified file
 . 5  ' '' 
. 6  
. 7  Import SYS
 . 8  Import to xlrd
 . 9  Import OS
 10  Import the logging
 . 11  
12 is  
13 is  # parameters and configuration functions provided logging.basicConfig logging.basicConfig () method 
14 the FORMAT = ' [% (funcName) S:% (lineno) D]:% (Message) S ' 
15 the LEVEL = logging.info
 16 logging.basicConfig (= the LEVEL Level, the format = the FORMAT)
 . 17  
18 is # 保存输出sheet name
19 output_file = './SheetNameList.txt'
20 
21 # init function
22 def get_obj_list(dir_name):
23     filelist = os.listdir(dir_name)
24     for item in filelist :
25         item = dir_name + item
26         if os.path.isfile(item) and ( item[-5:] == '.xlsx' or item[-5:] == '.xlsm'):
27             if item.find("$") != -1 or item.find("csr_example") != -1 :
28                 continue
29             GetSheetNameList(item)
30         elif os.path.isdir(item):    
31             item = item + '/'
32             new_obj_list = []
33             new_obj_list = get_obj_list(item)
34 
35 
36 # get sheet name and save in output_file
37 def GetSheetNameList(excelName):
38     fd = open(output_file, 'a+')
39     fd.write(excelName + '\n')
40     excelfd = xlrd.open_workbook(excelName)
41     for sheetName in excelfd.sheet_names():
42         fd.write(sheetName + '\n')
43     fd.close()
44 
45 
46 if __name__ == "__main__":
47     if os.path.exists(output_file):
48         os.remove(output_file)
49     get_obj_list('./excel/')

File Structure: