A hundred money to buy a hundred chicken C++ optimized version
The third optimization is to eliminate the equation to ensure the integer characteristic of the number of chickens.
#include<iostream>
using namespace std;
int main(){
system("pause");
//方案一
for (int cock = 0; cock <100; cock++)
{
for (int hen = 0; hen<100; hen++)
{
for (int chick = 0; chick <100; chick+=3)
{
if ((cock+hen+chick==100)&&(5*cock+3*hen+chick/3==100))
{
cout<<cock<<"," <<hen<<","<<chick<< endl;
}
}
}
}
//方案二
for (int cock = 0; cock < 20; cock++)
{
for (int hen = 0; hen<33; hen++)
{
for (int chick = 0; chick <100; chick+=3)
{
if ((cock + hen + chick == 100) && (5 * cock + 3 * hen + chick / 3 == 100))
{
cout << cock << "," << hen << "," << chick << endl;
}
}
}
}
//方案三
for (int cock1 = 0; cock1 < 16; cock1+=4)
{
int hen1 = 25 - 7 * cock1 / 4;
int chick1 = 1000 - cock1 - hen1;
cout << cock1 << "," << hen1 << "," << chick1 << endl;
}
cout << endl;
return 0;
}