"The Hundred Chicken Problem"

 Question: One chicken is worth five; one mother is worth three; three chicks are worth one. Hundreds of money to buy a hundred chickens, ask the chicken weng, the mother chicken, and the chicks?

Note: Buying 100 chickens with 100 dollars means that you just spend 100 dollars and you need to buy 100 chickens.

#include <stdio.h>
main()
{
    int x,y,z;
    for(x=1;x<=20;x++)
        for(y=1;y<=33;y++)
            for(z=3;z<=99;z+=3)
            {
                if((5*x+3*y+z/3==100)&&(x+y+z==100))/*Whether the conditions of Baiqian and Baiji are satisfied*/ printf("cock=%d ,hen=%d,chicken=%d\n",x,y,z);
            }
}

This kind of indefinite equation problem, the general solution:

Set the variable variable as a function, and then use the nested for loop to write out the value range of each variable.

Then in a nested for loop write out the relationship that the function should satisfy

Finally, use the printf statement to output each variable.