One chicken is worth five, a female chicken is worth three, a chick is three, worth one, a hundred money buys a hundred chickens, ask, how many chickens, female chickens and chicks?
Solution: Let x, y, z represent the number of chickens, hens, and chicks respectively, then the following equations can be cited:
x+y+z=100; 5x+3y+z/3=100; where x is at most 10, y is 33 at most. As long as the program can meet the above two conditions, the output
code is as follows:
#include <stdio.h>
void main(void){
int x,y,z;
for(x=1;x<=20;x++){
for(y=1;y<=33;y++){
z=100-x-y;
if((z%3==0)&&(5*x+3*y+z/3==100)){
printf("cook=%d,hen=%d,chiken=%d\n",x,y,z);
}
}
}
}