题目描述
创建一个空的顺序栈，并实现栈的入栈、出栈、返回栈的长度、返回栈顶元素、栈的遍历等基本算法。请将下面的程序补充完整。
#include<malloc.h>
#include<stdio.h>
#define OK 1
#define ERROR 0
#define STACK_INIT_SIZE 100 // 存储空间初始分配量
#define STACKINCREMENT 10 // 存储空间分配增量
typedef int SElemType; // 定义栈元素类型
typedef int Status; // Status是函数的类型,其值是函数结果状态代码，如OK等
struct SqStack
{
SElemType *base; // 在栈构造之前和销毁之后，base的值为NULL
SElemType *top; // 栈顶指针
int stacksize; // 当前已分配的存储空间，以元素为单位
}; // 顺序栈
Status InitStack(SqStack &S)
{
// 构造一个空栈S，该栈预定义大小为STACK_INIT_SIZE
// 请补全代码
}
Status Push(SqStack &S,SElemType e)
{
// 在栈S中插入元素e为新的栈顶元素
// 请补全代码
}
Status Pop(SqStack &S,SElemType &e)
{
// 若栈不空，则删除S的栈顶元素，用e返回其值，并返回OK；否则返回ERROR
// 请补全代码
}
Status GetTop(SqStack S,SElemType &e)
{
// 若栈不空，则用e返回S的栈顶元素，并返回OK；否则返回ERROR
// 请补全代码
}
int StackLength(SqStack S)
{
// 返回栈S的元素个数
// 请补全代码
}
Status StackTraverse(SqStack S)
{
// 从栈顶到栈底依次输出栈中的每个元素
SElemType *p = (SElemType *)malloc(sizeof(SElemType));
p = ______________________ //请填空
if()printf(“The Stack is Empty!”); //请填空
else
{
printf("The Stack is: ");
p–;
while() //请填空
{
printf("%d “, *p);
______________________ //请填空
}
}
printf(”\n");
return OK;
}
int main()
{
int a;
SqStack S;
SElemType x, e;
if() // 判断顺序表是否创建成功，请填空
{
printf(“A Stack Has Created.\n”);
}
while(1)
{
printf(“1:Push \n2:Pop \n3:Get the Top \n4:Return the Length of the Stack\n5:Load the Stack\n0:Exit\nPlease choose:\n”);
scanf("%d",&a);
switch(a)
{
case 1: scanf("%d", &x);
if() printf(“Push Error!\n”); // 判断Push是否合法，请填空
else printf(“The Element %d is Successfully Pushed!\n”, x);
break;
case 2: if() printf(“Pop Error!\n”); // 判断Pop是否合法，请填空
else printf(“The Element %d is Successfully Poped!\n”, e);
break;
case 3: if()printf(“Get Top Error!\n”); // 判断Get Top是否合法，请填空
else printf(“The Top Element is %d!\n”, e);
break;
case 4: printf(“The Length of the Stack is %d!\n”,______________________); //请填空
break;
case 5: ______________________ //请填空
break;
case 0: return 1;
}
}
}
输入格式
测试样例格式说明：
根据菜单操作：
1、输入1，表示要实现Push操作，紧跟着输入要Push的元素
2、输入2，表示要实现Pop操作
3、输入3，返回栈顶元素
4、输入4，返回栈的元素个数
5、输入5，表示从栈顶到栈底输出栈的所有元素
6、输入0，表示程序结束
输入样例
1
2
1
4
1
6
5
3
4
2
5
2
2
2
0
输出样例
A Stack Has Created.
1:Push
2:Pop
3:Get the Top
4:Return the Length of the Stack
5:Load the Stack
0:Exit
Please choose:
The Element 2 is Successfully Pushed!
1:Push
2:Pop
3:Get the Top
4:Return the Length of the Stack
5:Load the Stack
0:Exit
Please choose:
The Element 4 is Successfully Pushed!
1:Push
2:Pop
3:Get the Top
4:Return the Length of the Stack
5:Load the Stack
0:Exit
Please choose:
The Element 6 is Successfully Pushed!
1:Push
2:Pop
3:Get the Top
4:Return the Length of the Stack
5:Load the Stack
0:Exit
Please choose:
The Stack is: 6 4 2
1:Push
2:Pop
3:Get the Top
4:Return the Length of the Stack
5:Load the Stack
0:Exit
Please choose:
The Top Element is 6!
1:Push
2:Pop
3:Get the Top
4:Return the Length of the Stack
5:Load the Stack
0:Exit
Please choose:
The Length of the Stack is 3!
1:Push
2:Pop
3:Get the Top
4:Return the Length of the Stack
5:Load the Stack
0:Exit
Please choose:
The Element 6 is Successfully Poped!
1:Push
2:Pop
3:Get the Top
4:Return the Length of the Stack
5:Load the Stack
0:Exit
Please choose:
The Stack is: 4 2
1:Push
2:Pop
3:Get the Top
4:Return the Length of the Stack
5:Load the Stack
0:Exit
Please choose:
The Element 4 is Successfully Poped!
1:Push
2:Pop
3:Get the Top
4:Return the Length of the Stack
5:Load the Stack
0:Exit
Please choose:
The Element 2 is Successfully Poped!
1:Push
2:Pop
3:Get the Top
4:Return the Length of the Stack
5:Load the Stack
0:Exit
Please choose:
Pop Error!
1:Push
2:Pop
3:Get the Top
4:Return the Length of the Stack
5:Load the Stack
0:Exit
Please choose:
一般来说，这种填空的题目，理解了就会了，所以没什么好讲思路的，都是一个套路，实在不会的话就把代码背下来就好了，也就是几个常用函数。
代码如下
#include<malloc.h>
#include<stdio.h>
#define OK 1
#define ERROR 0
#define STACK_INIT_SIZE 100 // 存储空间初始分配量
#define STACKINCREMENT 10 // 存储空间分配增量
typedef int SElemType; // 定义栈元素类型
typedef int Status; // Status是函数的类型,其值是函数结果状态代码，如OK等
struct SqStack
{
SElemType *base; // 在栈构造之前和销毁之后，base的值为NULL
SElemType *top; // 栈顶指针
int stacksize; // 当前已分配的存储空间，以元素为单位
}; // 顺序栈
Status InitStack(SqStack &S)
{
S.base=(int *)malloc(STACK_INIT_SIZE*sizeof(char));
if(!S.base) return 0;
S.top=S.base;
S.stacksize=STACK_INIT_SIZE;
return OK;
}
Status Push(SqStack &S,SElemType e)
{
// 在栈S中插入元素e为新的栈顶元素
// 请补全代码
if(S.top-S.base==S.stacksize)
{
S.base=(int *)realloc(S.base,(S.stacksize+STACKINCREMENT)*sizeof(int));
if(!S.base) return 0;
S.top=S.base+S.stacksize;
S.stacksize+=STACKINCREMENT;
}
*S.top++=e;
return OK;
}
Status Pop(SqStack &S,SElemType &e)
{
// 若栈不空，则删除S的栈顶元素，用e返回其值，并返回OK；否则返回ERROR
// 请补全代码
if(S.base==S.top) return ERROR;
e=*--S.top;
return OK;
}
Status GetTop(SqStack S,SElemType &e)
{
// 若栈不空，则用e返回S的栈顶元素，并返回OK；否则返回ERROR
// 请补全代码
if(S.base==S.top) return ERROR;
e=*(S.top-1);
return OK;
}
int StackLength(SqStack S)
{
// 返回栈S的元素个数
// 请补全代码
return S.top-S.base;
}
Status StackTraverse(SqStack S)
{
// 从栈顶到栈底依次输出栈中的每个元素
SElemType *p = (SElemType *)malloc(sizeof(SElemType));
p = S.top; //请填空
if(S.top-S.base==0)printf("The Stack is Empty!"); //请填空
else
{
printf("The Stack is: ");
p--;
while(p>=S.base) //请填空
{
printf("%d ", *p);
p--; //请填空
}
}
printf("\n");
return OK;
}
int main()
{
int a;
SqStack S;
SElemType x, e;
if(InitStack(S)) // 判断顺序表是否创建成功，请填空
{
printf("A Stack Has Created.\n");
}
while(1)
{
printf("1:Push \n2:Pop \n3:Get the Top \n4:Return the Length of the Stack\n5:Load the Stack\n0:Exit\nPlease choose:\n");
scanf("%d",&a);
switch(a)
{
case 1: scanf("%d", &x);
if(!Push(S,x)) printf("Push Error!\n"); // 判断Push是否合法，请填空
else printf("The Element %d is Successfully Pushed!\n", x);
break;
case 2: if(!Pop(S,e)) printf("Pop Error!\n"); // 判断Pop是否合法，请填空
else printf("The Element %d is Successfully Poped!\n", e);
break;
case 3: if(!GetTop(S,e))printf("Get Top Error!\n"); // 判断Get Top是否合法，请填空
else printf("The Top Element is %d!\n", e);
break;
case 4: printf("The Length of the Stack is %d!\n",StackLength(S)); //请填空
break;
case 5: StackTraverse(S); //请填空
break;
case 0: return 1;
}
}
}
