《leetCode-php》分割链表

给出一个链表和一个值x,以x为参照将链表划分成两部分,使所有小于x的节点都位于大于或等于x的节点之前。

两个部分之内的节点之间要保持的原始相对顺序。

例如: 

给出1->4->3->2->5->2和x = 3,

返回1->2->2->4->3->5

思路:这个题目比较简单,搞两个链表分别存储两部分,然后链接起来即可

<?php
class Node {
    public $next = null;
    public $val;
    public function __construct($val) {
        $this->val = $val;
    }
}
function partition($head, $x) {
    $smallNode = new Node(0);
    $largeNode = new Node(0);
    $largeNode->next = $head;
    $node = $smallNode;
    $pre = $largeNode;
    while ($head != null) {
        if ($head->val < $x) {
            $tmp = $head->next;
            $head->next = $node->next;
            $node->next = $head;
            $pre->next = $tmp;
            $node = $node->next;
            $head = $tmp;
        } else {
            $pre = $head;
            $head = $head->next;
        }
    }
    $node->next = $largeNode->next;
    return $smallNode->next;
}
$node1 = new Node(1);
$node2 = new Node(4);
$node3 = new Node(3);
$node4 = new Node(2);
$node5 = new Node(5);
$node6 = new Node(2);
$node1->next = $node2;
$node2->next = $node3;
$node3->next = $node4;
$node4->next = $node5;
$node5->next = $node6;
$retNode = partition($node1, 3);
while ($retNode != null) {
    print $retNode->val . "\n";
    $retNode = $retNode->next;
}
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转载自blog.csdn.net/less_cold/article/details/102470063