水题,判断大小正多边形的中心是否重合.
思路:判断n能否整除m即可.
附ac代码:
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
int main(int argc, char const *argv[])
{
ll t;
cin >> t;
for (int i = 0; i < t; ++i)
{
ll m, n;
cin >> n >> m;
if (n % m == 0) cout << "YES" << endl;
else cout << "NO" << endl;
}
return 0;
}