poj 2010

没有ac的时候记得输出-1

#include <iostream>
#include <cstdio>
#include <iomanip>
#include <string>
#include <cstdlib>
#include <cstring>
#include <queue>
#include <set>
#include <vector>
#include <map>
#include <algorithm>
#include <cmath>
#include <stack>

#define INF 0x3f3f3f3f
#define LINF 0x3f3f3f3f3f3f3f3f
#define ll long long
#define ull unsigned long long
#define uint unsigned int
#define l(x) ((x)<<1)
#define r(x) ((x)<<1|1)
#define lowbit(x) ((x)&(-(x)))
#define abs(x) ((x)>=0?(x):(-(x)))
#define ms(a,b) memset(a,b,sizeof(a))
#define NSYNC std::ios::sync_with_stdio(false);std::cin.tie(0);std::cout.tie(0);

using namespace std;

struct node{
	int val,cost;
	int opo;
	bool operator<(const node &a){
		return val<a.val;
	}
};

int n,c,f,cl,cr;
node demo[222222];
priority_queue<int> q,qq;

int main(){	
	NSYNC;
	cin>>n>>c>>f;
	for(int i = 0;i<c;i++){
		cin>>demo[i].val>>demo[i].cost;
	}
	sort(demo,demo+c);
	
	cl = cr =0;
	for(int i = 0;i<n/2;i++) cl+=demo[i].cost,q.push(demo[i].cost);
	for(int i = n/2;i<c;i++){
		demo[i].opo = cl + demo[i].cost;
		cl+=demo[i].cost;
		q.push(demo[i].cost);
		cl-=q.top();
		q.pop();
	}
	
	for(int i = c-1;i>c-n/2-1;i--) cr+=demo[i].cost,qq.push(demo[i].cost);
	for(int i = c-n/2-1;i>=0;i--){
		demo[i].opo += cr;
		cr+=demo[i].cost;
		qq.push(demo[i].cost);
		cr-=qq.top();
		qq.pop();
	}

	bool flag = false;
	for(int i = c-n/2-1;i>=n/2;i--){
		//cout<<demo[i].opo<<" ";
		if(demo[i].opo<=f){
			printf("%d\n",demo[i].val);
			flag = true;
			break;
		}
	}
	//cout<<endl;
	if(!flag)printf("-1\n");
	
	int nnn;
	cin>>nnn;
	return 0;  
}
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转载自blog.csdn.net/Fawkess/article/details/103937666