Keras自定义IOU

def iou(y_true, y_pred, label: int):
    """
    Return the Intersection over Union (IoU) for a given label.
    Args:
        y_true: the expected y values as a one-hot
        y_pred: the predicted y values as a one-hot or softmax output
        label: the label to return the IoU for
    Returns:
        the IoU for the given label
    """
    # extract the label values using the argmax operator then
    # calculate equality of the predictions and truths to the label
    y_true = K.cast(K.equal(K.argmax(y_true), label), K.floatx())
    y_pred = K.cast(K.equal(K.argmax(y_pred), label), K.floatx())
    # calculate the |intersection| (AND) of the labels
    intersection = K.sum(y_true * y_pred)
    # calculate the |union| (OR) of the labels
    union = K.sum(y_true) + K.sum(y_pred) - intersection
    # avoid divide by zero - if the union is zero, return 1
    # otherwise, return the intersection over union
    return K.switch(K.equal(union, 0), 1.0, intersection / union)
        

def mean_iou(y_true, y_pred):
    """
    Return the Intersection over Union (IoU) score.
    Args:
        y_true: the expected y values as a one-hot
        y_pred: the predicted y values as a one-hot or softmax output
    Returns:
        the scalar IoU value (mean over all labels)
    """
    # get number of labels to calculate IoU for
    num_labels = K.int_shape(y_pred)[-1] - 1
    # initialize a variable to store total IoU in
    mean_iou = K.variable(0)
    
    # iterate over labels to calculate IoU for
    for label in range(num_labels):
        mean_iou = mean_iou + iou(y_true, y_pred, label)
        
    # divide total IoU by number of labels to get mean IoU
    return mean_iou / num_labels