统计一个数字在排序数组中出现的次数。
示例 1:
输入: nums = [5,7,7,8,8,10], target = 8
输出: 2
示例 2:
输入: nums = [5,7,7,8,8,10], target = 6
输出: 0
限制：
0 <= 数组长度 <= 50000
代码：
class Solution {
public int search(int[] nums, int target) {
if(nums.length==0)
{
return 0;
}
int left = 0,right = nums.length-1;
int mid = left +(right-left)/2;
while(left<right)
{
mid = left+(right-left)/2;
if(nums[mid]<target)
{
left = mid + 1;
}
else
{
right = mid;
}
}
int a = left;
left = 0;
right = nums.length-1;
while(left<right)
{
mid = (right-left)/2+left;
if(nums[mid]<=target)
{
left = mid+1;
}
else{
right = mid;
}
}
if(nums[right]==target)
{
return right- a+1;
}
else
{
return right - a;
}
}
}
