ziheng - 有返回值的函数

# 计算器: "3+5"
def cal(s):
    if '+' in s:
        s = s.split('+')
        # s:['88', '6']
        he = int(s[0]) + int(s[1])
        return he
    elif "*" in s:
        s = s.split('*')
        # s:['88', '6']
        he = int(s[0]) * int(s[1])
        return he
    else:
        return "我不会"


print(cal("12*94"))


# return 返回 remove删除
def shaokao(fen):
    print("来%d份烧烤"%fen)
    print("好嘞")
    print("疯狂制作中")
    print("极速上菜")
    return "%d份烧烤"%fen


print(shaokao(10))


# return 返回 remove删除
def shaokao2(fen):
    print("来%d份烧烤"%fen)
    print("好嘞")
    print("疯狂制作中")
    print("极速上菜")



print(shaokao2(10))



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转载自blog.csdn.net/houlaos/article/details/104605708