# 计算器: "3+5"
def cal(s):
if '+' in s:
s = s.split('+')
# s:['88', '6']
he = int(s[0]) + int(s[1])
return he
elif "*" in s:
s = s.split('*')
# s:['88', '6']
he = int(s[0]) * int(s[1])
return he
else:
return "我不会"
print(cal("12*94"))
# return 返回 remove删除
def shaokao(fen):
print("来%d份烧烤"%fen)
print("好嘞")
print("疯狂制作中")
print("极速上菜")
return "%d份烧烤"%fen
print(shaokao(10))
# return 返回 remove删除
def shaokao2(fen):
print("来%d份烧烤"%fen)
print("好嘞")
print("疯狂制作中")
print("极速上菜")
print(shaokao2(10))
ziheng - 有返回值的函数
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转载自blog.csdn.net/houlaos/article/details/104605708
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