PHP——取JSON属性值demo

<?php
    $json = '{"state":"1","info":"登录成功"}';
    $arr = (array) json_decode($json,true);
    echo '状态码:'. $arr['state'];

    $json2 = '{"data":{"date":"2019-02-09","team":"第二学期"}}';
    $arr2 = (array) json_decode($json,true);
    echo '日期:'. $arr2['data']['date'].'学期:'.$arr2['data']['team'];
?>
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