python路径拼接os.path.join()函数的用法

os.path.join()函数：连接两个或更多的路径名组件

1.如果各组件名首字母不包含’/’，则函数会自动加上

demo1

import os

Path1 = 'home'
Path2 = 'develop'
Path3 = 'code'

Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1,Path2,Path3)
print ('Path10 = ',Path10)
print ('Path20 = ',Path20)

输出：

Path10 =  homedevelopcode
Path20 =  home\develop\code

2.如果有一个组件是一个绝对路径，则在它之前的所有组件均会被舍弃

demo2

import os

Path1 = '/home'
Path2 = 'develop'
Path3 = 'code'

Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1, Path2, Path3)
Path30 = os.path.join(Path2, Path1, Path3)
print('Path10 = ',Path10)
print('Path20 = ',Path20)
print('Path30 = ',Path30)

　输出：

Path10 =  /homedevelopcode
Path20 =  /home\develop\code
Path30 =  /home\code

3.如果最后一个组件为空，则生成的路径以一个’/’分隔符结尾

demo3

import os

Path1 = 'home'
Path2 = 'develop'
Path3 = ''

Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1, Path2, Path3)
Path30 = os.path.join(Path2, Path1, Path3)
print('Path10 = ',Path10)
print('Path20 = ',Path20)

输出：

Path10 =  homedevelop
Path20 =  home\develop\