leetcode1344

1 class Solution:
2     def angleClock(self, hour: int, minutes: int) -> float:
3         m_angle = minutes * 6
4         h_angle = (hour + minutes / 60) * 6 * 5 if hour != 12 else (minutes / 60) * 6 * 5
5         diff = abs(m_angle - h_angle)
6         diff = min(diff,360-diff)
7         return diff

算法思路:先计算分针的角度。再计算时针的角度。取两个角度的差的绝对值,再取锐角。

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转载自www.cnblogs.com/asenyang/p/12286226.html
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